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Katena32 [7]
3 years ago
6

9/16, 0.25, 5/48, 0.5 least from greatest

Mathematics
2 answers:
KIM [24]3 years ago
6 0

Answer: 0.1 (5/48) (Least) , 0.25, 0.5, 0.56 (9/16) (Greatest)

Step-by-step explanation:

I changed the fractions into decimals so 9/16 would equal 0.56 and 5/48 equals 0.1.

zubka84 [21]3 years ago
4 0

Answer:

9/16, 0.5, 0.25, 5/48

Step-by-step explanation:

hope this helps

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What is the slope of the line through the points (-3,3) and (6,-8)
STatiana [176]

Answer:

\displaystyle \frac{-11}{9}

Step-by-step explanation:

       We will use the equation of change in y over change in x to solve for the slope of the line. Then, we will simplify.

\displaystyle \frac{y_{2}-y_1 }{x_2-x_1}

\displaystyle \frac{-8-3}{6--3}

\displaystyle \frac{-8-3}{6+3}

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Find the following limit or state that it does not exist. ModifyingBelow lim With x right arrow minus 2 StartFraction 3 (2 x min
leva [86]

Answer:

-60

Step-by-step explanation:

The objective is to state whether or not the following limit exists

                                \lim_{x \to -2}  \frac{3(2x-1)^2 - 75}{x+2}.

First, we simplify the expression in the numerator of the fraction.

3(2x-1)^2 -75 = 3(4x^2 - 4x +1) -75 = 12x^2 - 12x + 3 - 75 = 12x^2 - 12x -72

Now, we obtain

                         12(x^2-x-6) = 12(x+2)(x-3)

and the fraction is transformed into

                       \frac{3(2x-1)^2 - 75}{x+2} =  \frac{12(x+2)(x-3)}{x+2} = 12 (x-3)

Therefore, the following limit is

       \lim_{x \to -2}  \frac{3(2x-1)^2 - 75}{x+2} = \lim_{x \to -2}  12(x-3) = 12 \lim_{x \to -2} (x-3)

You can plug in -2 in the equation, hence

                        12 \lim_{x \to -2} (x-3) = 12 (-2-3) = -60

6 0
4 years ago
What is the solution to the following system of linear equations?
Lostsunrise [7]
<span> x − 2y = −1 => x = 2y -1

2x + y = −12
2(2y - 1) + y = -12
4y - 2 + y = -12
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y = -2
x = 2</span>·(-2) - 1
x = -4 - 1
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Answer <span>D (-5,-2)</span>
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Answer:

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