Find the area of a triangle

Mathematics

1 answer:

lana66690 [7]3 years ago

4 0

Answer: 68

Step-by-step explanation:

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A rectangular box has a length of 8 feet and a width of 2 feet. The length of the three-dimensional diagonal is 10 feet. What is

harkovskaia [24]

Answer: $h=5.66ft$

Step-by-step explanation:

Observe the picture attached.

Find the value of "x" and "y" using the Pythagoren Theorem:

$a^2=b^2+c^2$

If you solve for "a":

$a= \sqrt{b^2+c^2}$

Where "a" is the hypotenuse and "b" and "c" are the legs.

In this case, for "x" you know that:

$a=x\\b=8ft\\c=2ft$

Then, the value of "x" is:

$x=\sqrt{(8ft)^2+(2ft)^2}\\\\x=8.24ft$

For "y" you can see that:

$a=10ft\\b=8.24ft\\c=h$

Subsituting values and solving for h, you get:

$(10ft)^2=(8.24ft)^2+h^2\\\\h=\sqrt{(10ft)^2-(8.24ft)^2} \\\\h=5.66ft$

3 0

4 years ago

Is the line through points p(-3,-2) and Q(2,3) perpendicular to the line through points R(10,1) and S(15,-6)?

Katen [24]

The slope of line PQ is m1 = ( 3 - (-3) ) / (2 - (-2) ); then m1 = 6/4 = 3/2;
In the same way, the slope of line RS is m2 = -7/5;
But (3/2) x (-7/5) = -21/10, which is diferrent from - 1;
So, the lines aren't perpendicular.

6 0

3 years ago

23 is 12% of what number

Anon25 [30]

$\frac { 12 }{ 100 } \cdot x=23\\ \\ \Rightarrow \quad \frac { 3 }{ 25 } \cdot x=23\\ \\ \Rightarrow \quad \frac { 25 }{ 3 } \cdot \frac { 3 }{ 25 } \cdot x=23\cdot \frac { 25 }{ 3 } \\ \\ \Rightarrow \quad x=\frac { \left( 20+3 \right) \left( 25 \right) }{ 3 } \\ \\ \Rightarrow \quad x=\frac { 500+75 }{ 3 } \\ \\ \Rightarrow \quad x=\frac { 575 }{ 3 }$