The answer to this very difficult question is 10 :)
The solution for proving the identity is as follows:
sin(2A) = sin(A + A)
As sin(a + b) = sinacosb + sinbcosa,
<span>sin(A + A) = sinAcosA + sinAcosA
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<span>Therefore, sin(2A) = 2sinAcosA
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your inquiries and questions soon. Have a nice day ahead!
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Answer:
(x + 1)/4x² + 4(x + 1)/4x²
Step-by-step explanation:
x+1/4x² + x+1/x²
The above can be simply as follow:
Find the least common multiple (LCM) of 4x² and x². The result is 4x²
Now Divide the LCM by the denominator of each term and multiply the result with the numerator as show below:
(4x² ÷ 4x²) × (x + 1) = x + 1
(4x² ÷ x²) × (x + 1) = 4(x + 1)
x+1/4x² + x+1/x² = [(x + 1) + 4(x + 1)]/ 4x²
= (x + 1)/4x² + 4(x + 1)/4x²
Therefore,
x+1/4x² + x+1/x² = (x + 1)/4x² + 4(x + 1)/4x²
Answer:
A=πr2
Step-by-step explanation:
