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NeTakaya
3 years ago
14

Similar triangles practice worksheet for problems 1-5 below identify if the triangles are similar or not

Mathematics
1 answer:
Sholpan [36]3 years ago
8 0
They are very simalar btw weres the triangles
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19. The present age of brother and sister are in the ration 4:5 Before three years the ration of their age was 3:4. find their p
Lyrx [107]

Answer:

Sister = 15 years old

Brother = 12 years old

Step-by-step explanation:

Right now, if the brother is B years old and the sister is S years old, B = (4/5)S because the ratio from brother to sister is 4:5, so if one unit is X, B = 4X and S = 5X

Three years ago, the brother was B-3 years old and the sister was S-3 years old. Keeping one unit as X, we have

B = 3X

S = 4X

B-3 = (3/4)(S-3)

Therefore, we have a system of equations

B = (4/5)S

B-3 = (3/4)(S-3)

Substitute (4/5)S for B into the second equation to only have one variable

(4/5)S - 3 = (3/4)(S-3)

(4/5)S - 3 = (3/4)S - 9/4

add 3 to both sides and subtract (3/4)S from both sides to isolate the variable and its coefficient

(1/20)S = 3/4

multiply both sides by 20 to isolate the S

S = 15

B = (4/5)S = 12

5 0
3 years ago
Really need help with this pls help!!
worty [1.4K]

Let's carry this math sentence over to its natural, "shapey" element. We're going to look at each term not as an ordinary number, but as <em>the area of some shape</em>.

x² (read as "x <em>squared"</em>) can be seen as the area of a square with side lengths of x. 2x can similarly be seen as the area of a <em>rectangle </em>with a length of x and a width of 2. (Picture 1)

What's our question actually asking, though? Something about <em>perfect squares</em>. More specifically, we're looking for something to add on that'll <em>make this thing a perfect square</em>. We're trying to find a missing piece we can slot in to make a square, in other words. Problem is, our shapes don't look much like a square if we put them together right now. We need to do a little cutting and gluing first.

First, we're gonna cut the 2x rectangle lengthwise, getting two rectangles with an area of x, a length of 1, and a width of x. Next, we're going to attach them to the x² square, creating this shape that looks, strangely, like a square with a little bit missing from it (picture 2). What we're trying to do is <em>complete this square, </em>to find the area of that little missing chunk.

As it turns out, we have all the information we need for this. Notice that, using the lengths of the x rectangles, we can find that the square's dimensions are 1 x 1, which means that its area is 1 x 1  = 1.

If we tack this new area on to our original expression, we've "completed the square!" We now have a perfect square with side lengths of (x + 1) and an area of (x + 1)² (picture 3).

So, our final expression is x² + 2x + 1, and the missing constant - the area of the "missing square" we had to find to complete our larger one - is 1.

5 0
4 years ago
Read 2 more answers
At the deli counter Sandy bought 1 3/4 pounds of cheese for 4$ per pound and 2 1/4 pounds of turkey for 6$ per pound. How much d
Bogdan [553]

Answer:

10 dollars

Step-by-step explanation:

4 + 6 = 10 which mean 10 dollars spent

4 0
3 years ago
Generate an equivalent expression using prime factorization for -60. show your workk ​
Darina [25.2K]

Answer:

60 70 80m9

Step-by-step explanation:

4 0
3 years ago
-12u+3=8v+1 helppppp me out wit this
Pavlova-9 [17]

Subtract 3 from both sides

-12u = 8v + 1 - 3

Simplify 8v + 1 - 3 to 8v - 2

-12u = 8v - 2

Divide both sides by -12

u = - 8v - 2/12

Factor out the common term 2

u = - 2(4v - 1)/12

Simplify 2(4v - 1)/12 to 4v - 1/6

u = - 4v - 1/6

4 0
3 years ago
Read 2 more answers
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