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Law Incorporation [45]
3 years ago
13

A car company is trying out a new promotion where they give the customer 6 candy canes if they buy a set of four new tires. What

is the ratio of candy canes to tires.
Mathematics
1 answer:
alexgriva [62]3 years ago
6 0

Answer:

6:4

Step-by-step explanation:

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The number of boys of grade 6 students is 220.This is 40more than number of boys grade seven students. How many grade seven boy
belka [17]

Answer:

Given

no of Grade 6 students = 220

no of Grade 7 students = 40 more than grade 6 students

Step-by-step explanation:

boys Grade 7 students = no of Grade 6 students - 40 more than grade 6 students

boys Grade 7 students = 220 - 40

boys Grade 7 students = <u>180 grade 7 boy students are enrolled</u>

Therefore, 180 grade 7 boy students are enrolled.

6 0
2 years ago
Solve 2x+7=16 pls help meee​
Black_prince [1.1K]

Answer:

5.5

Step-by-step explanation:

2x+7=16

   -7   -7

2x=11

2x/2=11/2

x=5.5

6 0
3 years ago
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The three sides of an equilateral triangle measure (x + 12), (2x - 5) and (3x - 22) inches. The sides of the triangle measure
agasfer [191]
All 3 sides are equal in an equilateral triangle...

2x - 5 = 3x - 22
-5 + 22 = 3x - 2x
17 = x

2x - 5 = 2(17) - 5 = 34 - 5 = 29
3x - 22 = 3(17) - 22 = 51 - 22 = 29
x + 12 = 17 + 12 = 29

as u can see, all sides measure 29 inches
8 0
3 years ago
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HELP PLEASEEE ASAP ! THANK YOU :)
Salsk061 [2.6K]

Answer:

f(x) = 2x³ - 6x² - 48x + 24

relative minimum: (4,-136)

relative maximum: (-2,80)

answer is the second option

6 0
4 years ago
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The measurement of the radius of the end of a log is found to be 9 inches, with a possible error of 1/2 inch. Use differentials
enot [183]

Answer:

\pm 9in^2

Step-by-step explanation:

We are given that

Radius of end of a log, r= 9 in

Error, \Delta r=\pm 1/2in

We have to find the error in computing the area of the end of the log by using differential.

Area of end of the log, A=pi r^2

\frac{dA}{dr}=2\pi r

\frac{dA}{dr}=2\pi (9)=18\pi in^2

Now,

Approximate error in area

dA=\frac{dA}{dr}(\Delta r)

Using the values

dA=18\pi (\pm 1/2)

\Delta A\approx dA=\pm 9in^2

Hence, the possible propagated error in computing the area of the end of the log=\pm 9in^2

6 0
3 years ago
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