Statistics should be used because the temperature would vary during January and you would want to give an accurate answer.
The expression that would be added to both sides is (b/2a)^2
<h3>How to determine the expression?</h3>
The equation is given as:
x^2 + b/ax + __ = c/a + __
Take the coefficient of x
b/a
Divide by 2
b/2a
Square the expression
(b/2a)^2
Hence, the expression that would be added to both sides is (b/2a)^2
Read more about quadratic equation at:
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5.
f(K) = D^3 => f(25) = 125 => 25 * t = 125 ( because K is directly proportional with D^3 )=> t = 125 / 25 => t = 5 => f(25) = 25 * 5 => K * 5 = D^3 ;
6.
f(L) = F^3 => f(2) =3^3 =>f(2) = 27 => 2 / t =27 => t = 2 / 27 => t = 0.074 => f(2) = 2 / 0.074 => K / 0.074 = F^3 ;
Answer: Kelsey had $65 to spend on books. Each book cost $5.50, and there was a $7.50 fee for shipping. She let b equal the number of books she can purchase
Step-by-step explanation:
Simplify:
37 - (-3)^2 + 30/(-3)x^2
= 37 + - 9 + - 10x^2
Combine like terms:
= 37 + - 9 + - 10x^2
= ( - 10x^2) + (37 + - 90
= - 10X^2 + 28
Answer: - 10x^2 + 28
To Factor:
37 - (- 3)^2 + 30/- 3x^2
- 10x^2 + 28
- 2(5x^2 - 14)
Answer: - 2(5x^2 - 14)
I simplify, and factor, because, you didn't really specify what you wanted help on with this equation. - Thanks -
Hope that helps!!!!
