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dedylja [7]
2 years ago
6

Solve questions 1-10 I just need the answer in (x,y) form

Mathematics
1 answer:
Andre45 [30]2 years ago
5 0

Answer:

1. (1,1)

2.(2,-6)

3.Not sure.

4.No solution

5.(-3,4)

6. (6,-4)

7.(7,2)

8.(-7,-12)

9.(9,-1)

10.(2,1)

Step-by-step explanation:

Hope that helps bud!:)

You might be interested in
A circular picture is 8 inches in diameter.
erma4kov [3.2K]

Answer:

Part A :

Area = π*r² = π(d/2)² = π*(8/2)² =

π*4² = π*16 square inches

Part B:

d=8+4 = 12 and r = d/2 = 6 inches

We know :

Area = π*r²

Area = π*6²

=36π

<u><em>Hope This Answer To Your Question!  </em></u>

8 0
3 years ago
There are 50 pages in a chapter. Claire read 17 pages of the chapter on Sunday.
nexus9112 [7]

Answer:

She read 34% of the chapter

Step-by-step explanation:

You divide 17 by 50 and that gives you your answer

17/50=.34

move the decimal point 2 places to the right and the gives you your precent

.34=34%

5 0
2 years ago
Al factorizar el trinomio cuadrado perfecto, obtenemos el siguiente resultado: (que no se como resolver) xd algun pro que sepa r
PolarNik [594]

Answer:

\displaystyle \frac{100}{81}m^8p^{12}q^{16}z^2-\frac{20}{63}m^5p^7q^8z^5+ \frac{1}{49}m^2p^2z^8=\left(\frac{10}{9}m^4p^{6}q^{8}z-\frac{1}{7}mpz^4\right)^2

Step-by-step explanation:

<u>Trinomio Cuadrado Perfecto</u>

El producto notable llamado cuadrado de un binomio se expresa como:

(a-b)^2=a^2-2ab+b^2

Si se tiene un trinomio, es posible convertirlo en un cuadrado perfecto si cumple con las condiciones impuestas en la fórmula:

* El primer término es un cuadrado perfecto

* El último término es un cuadrado perfecto

* El segundo término es el doble del proudcto de los dos términos del binomio.

Tenemos la expresión:

\displaystyle \frac{100}{81}m^8p^{12}q^{16}z^2-\frac{20}{63}m^5p^7q^8z^5+ \frac{1}{49}m^2p^2z^8

Calculamos el valor de a como la raiz cuadrada del primer término del trinomio:

\displaystyle a=\sqrt{\frac{100}{81}m^8p^{12}q^{16}z^2}

\displaystyle a=\frac{10}{9}m^4p^{6}q^{8}z

Calculamos el valor de a como la raiz cuadrada del primer término del trinomio:

\displaystyle b=\sqrt{\frac{1}{49}m^2p^2z^8

\displaystyle b=\frac{1}{7}mpz^4

Nos cercioramos de que el término central es 2ab:

\displaystyle 2ab=2\frac{10}{9}m^4p^{6}q^{8}z\frac{1}{7}mpz^4

Operando:

\displaystyle 2ab=\frac{20}{63}m^5p^7q^8z^5

Una vez verificado, ahora podemos decir que:

\displaystyle \frac{100}{81}m^8p^{12}q^{16}z^2-\frac{20}{63}m^5p^7q^8z^5+ \frac{1}{49}m^2p^2z^8=\left(\frac{10}{9}m^4p^{6}q^{8}z-\frac{1}{7}mpz^4\right)^2

5 0
2 years ago
I have a pile of 20 coins that includes dimes and quarters. The coins total is $2.75. How many quarters do I have?
Ilia_Sergeevich [38]
You have 5 quarters which equals 25 cents each. Which in total comes to $1.25.
You have 15 dimes which is worth 10 cents each.
Which in total comes to $1.50.
$1.50
+$1.25
=$2.75
5 0
3 years ago
How to do this plastic help​
liraira [26]

Answer:

39 degrees

Step-by-step explanation:

  • by seeing the diagram in the attachment, we can see that the angles UWV and VWX are on straight line or, their sum makes 180 degrees.
  • we also know that sum of the angles in a triangle is 180 degrees.

by using the first statement,

UWV + VWX = 180

UWV + 6x-3 = 180

UWV = 180+3-6x

         = 183-6x

by using second statement,

UWV+WVU+VUW=180

substituting the values,

183-6x+2x+5+x+13=180

201-3x=180

substracting 180 from both sides,

21=3x

dividing both the sides by 3,

7=x

the angle VWX=6x-3

substituting 7=x,

VWX=6(7)-3= 39.

4 0
3 years ago
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