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tester [92]
3 years ago
7

Emily is going to the movies this weekend with some friends. they have a total of $54 to spend. Emily wants a large popcorn that

is $12. If each movie ticket costs $6, how many tickets can Emily buy?
Mathematics
2 answers:
Anestetic [448]3 years ago
8 0
6x+12=54

6x+12=54
-12 -12
———————
6x = 42
——————-
6x 6x = 7


The answer will be 7
timurjin [86]3 years ago
3 0
Answer is 7

You have to do

54 - 12= 42

Then divide 42 by 6 which equals 7
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Which statements are true about the ordered pair (2, 3) and the system of equations?
kifflom [539]
The answer is f when 2,3 is put in for the x and y then 18 should come out 3×2=6
4×3=12 12+6=18
7 0
4 years ago
N is an integer.<br> Write the values of n such that -15 &lt; 3 ≤ 6<br><br> Help please ❤️❤️
Alex17521 [72]

Answer:

-4,-3,-2,-1,0,1

Step-by-step explanation:

First, doublepound and simplify it.

-15<3n

3n<6

Solve:

-5<n

n<2

Compound:

-5<n<2.

So the values are -4,-3,-2,-1,0,1

Hope this helps plz hit the crown :D

8 0
3 years ago
Read 2 more answers
Help please I will give brainliest for the correct answer (166 is wrong but I get one more try)​
lys-0071 [83]

Answer:

136

Step-by-step explanation:

multiply 4 times 6, divide by two to get the area of the front side, then multiply that by two to get eh area of the two triangles.

Then multiply each side, two sides of 5 time 7 and one side of 6 times 7

7 0
3 years ago
Coach Evans recorded the height, in inches of each player on his team. The results are shown.
marysya [2.9K]

Answer:

3

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile (Q_1)

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile (Q_3)

Terms in arranged in ascending order:

57,60,60,61,62,62,63,63,64

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

Q_1 is median of terms 57,60,60,61

Number of terms (n) = 4

Median = \frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th}  }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{60+60}{2}=\frac{120}{2}=60

So, Q_1=60

So, 25% of the heights of a team is less than 60 inches

Q_3 is the median of terms 62,63,63,64

Median = \frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th}  }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63

So, Q_3=63

So, 75% of the heights of a team is less than 63 inches

Interquartile range = Q_3-Q_1=63-60=3

The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

4 0
3 years ago
How do I fill this out? Im not sure how to?
prohojiy [21]

Answer:

z=-21

Step-by-step explanation: (9-3)/2=(6+z)/5

We move all terms to the left:

(9-3)/2-((6+z)/5)=0

We add all the numbers together, and all the variables

-((z+6)/5)+6/2=0

We add all the numbers together, and all the variables

-((z+6)/5)+3=0

We multiply all the terms by the denominator

-((z+6)+3*5)=0

We calculate terms in parentheses: -((z+6)+3*5), so:

(z+6)+3*5

We add all the numbers together, and all the variables

(z+6)+15

We get rid of parentheses

z+6+15

We add all the numbers together, and all the variables

z+21

Back to the equation:

-(z+21)

We get rid of parentheses

-z-21=0

We add all the numbers together, and all the variables

-1z-21=0

We move all terms containing z to the left, all other terms to the right

-z=21

z=21/-1

z=-21

5 0
3 years ago
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