In looking at it I would guess it is asking which of the points is on the line? To answer that you would have to take each point an plug it into the equation and see if it is true.
3x - 7 = y
A(9,20)
3(9) - 7 = 20
27 - 7 = 20
20 = 20 True - this point is on the line
B(5,0)
3(5) - 7 = 0
15 - 7 = 0
8 = 0 False - this point is not on the line
C(3,2)
3(3) - 7 = 2
9 - 7 = 2
2 = 2 True - this point is on the line
I hope this helps
She had 45$ before she spent it. 30+15
Answer:
27 and 32.
Step-by-step explanation:
Let the two numbers be A and B.
The larger number (let's use B) is 5 more than the smaller one (A). In other words:

Their sum is 59. So:

This is a system of equations. Solve by substituting the first equation into the second. Thus:

Combine like terms:

Subtract 5 from both sides:

Divide both sides by 2:

So, the smaller number is 27.
This means that the bigger number is 27+5=32.
So, the two numbers are 27 and 32.
And we're done!
Answer: They would be a rectangle.
Step-by-step explanation:
2 right angles need at least 4 sides, making it impossible to have a 3-sided 2 right angle triangle.
Answer:
% change in stopping distance = 7.34 %
Step-by-step explanation:
The stooping distance is given by

We will approximate this distance using the relation

dx = 26 - 25 = 1
T' = 2.5 + x
Therefore

This is the stopping distance at x = 25
Put x = 25 in above equation
2.5 × (25) + 0.5×
+ 2.5 + 25 = 402.5 ft
Stopping distance at x = 25
T(25) = 2.5 × (25) + 0.5 × 
T(25) = 375 ft
Therefore approximate change in stopping distance = 402.5 - 375 = 27.5 ft
% change in stopping distance =
× 100
% change in stopping distance = 7.34 %