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3 years ago

(iv) The area of a rectangle with breadth5 cm is 30 sq. cm. Find its length andperimeter.

Mathematics

1 answer:

Nataly_w [17]3 years ago

3 0

Answer:

Step-by-step explanation:

if the breadth is 5cm, then you divide 30/5 to get your length since it's length times breadth to get the area, so 6cm for the length

and then it's 2b plus 2l to get your perimeter so

2(5)+2(6)=p

10 plus 12 equals p

22 is your perimeter, 6 is your length

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Solve: x2 − x − 6/x2 = x − 6/2x + 2x + 12/x After multiplying each side of the equation by the LCD and simplifying, the resultin

Vesna [10]

The resulting equation after simplyfing the given equation is 3x^2 + 20x + 12 = 0 and whoose solutions are x = -2/3 or x = -6.

According to the given question.

We have an equation

$\frac{x^{2}-x-6 }{x^{2} } = \frac{x-6}{2x} +\frac{2x+12}{x}$

So, to find the resulting equation of the above equation we need to simplify.

First we will take LCD

$\frac{x^{2} -x - 6 }{x^{2} } = \frac{x -6+2(2x + 12)}{2x}$

$\implies \frac{x^{2}-x-6 }{x^{2} } =\frac{x-6+4x+24}{2x}$

$\implies \frac{x^{2}-x-6 }{x^{2} } = \frac{5x +18}{2x}$

Multiply both the sides by x.

$\frac{x^{2}-x-6 }{x} = \frac{5x+18}{2}$

Again multiply both the sides by x

$2x^{2} -2x-12 = 5x^{2} +18x$

$\implies 5x^{2} -2x^{2} +18x +2x +12 = 0$

$\implies 3x^{2} + 18x+2x + 12 = 0$

Factorize the above equation

⇒3x(x+6)+2(x+6) = 0

⇒(3x + 2)(x+6) = 0

⇒ x = -2/3 or x = -6

Hence, the resulting equation after simplyfing the given equation is 3x^2 + 20x + 12 = 0 and whoose solutions are x = -2/3 or x = -6.

Find out more information about equation here:

brainly.com/question/2976807

#SPJ4

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1 year ago

-3x+10=21 solve for x

Fed [463]

Answer:

Step-by-step explanation:

-3x+10=21

-3x=21-10

-3x=11

x=11/-3

x=- 11/3

8 0

3 years ago

PART B

Anastasy [175]

Answer: quit

Step-by-step explanation:

8 0

3 years ago

Solve x squared minus 2x minus 15 equals 0 using the zero product property

Pani-rosa [81]

X^2 - 2x - 15 = 0

(x - 5)(x + 3) = 0

We have two factors:

(x - 5) and (x + 3)

Set each factor to 0 and solve for x.

Take it ftom here.

4 0

3 years ago

Suppose that a box contains one fair coin (Heads and Tails are equally likely) and one coin with Heads on each side. Suppose fur

stealth61 [152]

Using conditional probability, it is found that there is a 0.1 = 10% probability that the chosen coin was the fair coin.

Conditional Probability

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.
$P(A \cap B)$ is the probability of both A and B happening.
P(A) is the probability of A happening.

In this problem:

Event A: Three heads.
Event B: Fair coin.

The probability associated with 3 heads are:

$0.5^3 = 0.125$ out of 0.5(fair coin).
1 out of 0.5(biased).

Hence:

$P(A) = 0.125 + 0.5 = 0.625$

The probability of 3 heads and the fair coin is:

$P(A \cap B) = 0.5(0.125) = 0.0625$

Then, the conditional probability is:

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0625}{0.625} = 0.1$

0.1 = 10% probability that the chosen coin was the fair coin.

A similar problem is given at brainly.com/question/14398287

4 0

3 years ago

(iv) The area of a rectangle with breadth5 cm is 30 sq. cm. Find its length andperimeter.​

(iv) The area of a rectangle with breadth5 cm is 30 sq. cm. Find its length andperimeter.