How do u solve this ?

Write an equation for the cubic polynomial function whose graph has zeroes at 2, 3, and 5. Write the polynomial function for the

forsale [732]

Answer:

f(x) = (x - 2)(x - 3)(x - 5)

f(x) = x³ - 10x² + 31x - 30

Step-by-step explanation:

We have to write the equation for the cubic polynomial function whose graph has zeroes at 2, 3, and 5.

That means at x = 2, x = 3 and at x = 5 the function f(x) will become zero.

Therefore, (x - 2), (x - 3) and (x - 5) are the factors of the function f(x).

Ans the cubic function is f(x) = (x - 2)(x - 3)(x - 5) .......... (1) (Answer)

Now, we have to simplify the right hand side of the equation (1).

Hence, f(x) = (x - 2)(x² - 8x + 15)

⇒ f(x) = x³ - 8x² + 15x - 2x² + 16x - 30

⇒ f(x) = x³ - 10x² + 31x - 30

So, this is the requires equation. (Answer)

5 0

4 years ago

Rewrite in simplest terms (-9x-2y)+(4x-5y)

Evgesh-ka [11]

Answer:

-5x - 7y

Step-by-step explanation:

8 0

3 years ago

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Construct a line that is perpendicular to

kodGreya [7K]

1) The line will need to be vertical down the point of x, meaning draw a line down point x. Perpendicular lines look similar to t’s
2.) Same thing, just draw a line through point O and the line. They should look similar to t’s
Hope this helped!! I understand math can get really hard, soon it’ll all be over :)

5 0

3 years ago

During the 2015-16 NBA season, J.J. Redick of the Los Angeles Clippers had a free throw shooting percentage of 0.901 . Assume th

ser-zykov [4K]

Answer: 0.5898

Step-by-step explanation:

Given : J.J. Redick of the Los Angeles Clippers had a free throw shooting percentage of 0.901 .

We assume that,

The probability that .J. Redick makes any given free throw =0.901 (1)

Free throws are independent.

So it is a binomial distribution .

Using binomial probability formula, the probability of getting success in x trials :

$P(X=x)^nC_xp^x(1-p)^{n-x}$

, where n= total trials

p= probability of getting in each trial.

Let x be binomial variable that represents the number of a=makes.

n= 14

p= 0.901 (from (1))

The probability that he makes at least 13 of them will be :-

$P(x\geq13)=P(x=13)+P(x=14)$

$=^{14}C_{13}(0.901)^{13}(1-0.901)^1+^{14}C_{14}(0.901)^{14}(1-0.901)^0\\\\=(14)(0.901)^{13}(0.099)+(1)(0.901)^{14}\ \ [\because\ ^nC_n=1\ \&\ ^nC_{n-1}=n ]\\\\\approx0.3574+0.2324=0.5898$

∴ The required probability = 0.5898

5 0

3 years ago

A tip employee’s earnings most closely resemble those of which of the following? a. An employee working on straight commission b

Lelechka [254]

Your answer would be C

6 0

3 years ago

Read 2 more answers