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anzhelika [568]
3 years ago
15

FIND THE LENGTH AND WIDTH OF THE RECTANGLE

Mathematics
2 answers:
insens350 [35]3 years ago
7 0
W = width
3w + 7 = length

Equation: 3w + 7 + w = 75
Combine like terms: 4w + 7 = 75
Subtract 7 to the other side: 4w = 68
Divide both sides by 4: w = 17

Width = 17
Length = 3(17) + 7, so 58
BaLLatris [955]3 years ago
6 0

Answer:

w=7  5/8

l = 29.875

Step-by-step explanation:

We have to use system of equations here

Let l be length and w be width

l = 3w+7

w=l(1/3)-7

We can use the equation:

l+w+l+w = 75

2l+2w = 75

Now we substitute l for what we said above

2(3w+7)+2w=75

6w+14+2w=75

Combine like terms

8w+14=75

Subtract 14 on both sides

8w=61

w=7  5/8

We can use what we know about the relationship of the width and the length to find the length

7  5/8 * 3 + 7 = 29.875

l = 29.875

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mel-nik [20]

Answer:

15/4, or 3 3/4 is your answer.

Step-by-step explanation:

Isolate the variable, t. Note the equal sign, what you do to one side, you do to the other. Multiply 3/2 to both sides.

(3/2)(2/3)t = (5/2)(3/2)

t = (5/2)(3/2)

t = 15/4

15/4, or 3 3/4 is your answer.

~

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3 years ago
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Answer:

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Step-by-step explanation:

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$9.97 - $9.57 = $0.40

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3 years ago
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Nitella [24]

Answer:

  • y(2x² + y) / x(5y² - 6x)

Step-by-step explanation:

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<u>Simplify the fraction:</u>

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2 years ago
Read 2 more answers
2/3x - 11 = x/3 + 3
Grace [21]
2
3

−
1
1
=

3
+
3
2
3
x
−
11
=
x
3
+
3
32​x−11=3x​+3
2

3
−
1
1
=

3
+
3
2
x
3
−
11
=
x
3
+
3
32x​−11=3x​+3
2
Find common denominator
2

3
−
1
1
=

3
+
3
2
x
3
−
11
=
x
3
+
3
32x​−11=3x​+3
2

3
+
3
(
−
1
1
)
3
=

3
+
3
2
x
3
+
3
(
−
11
)
3
=
x
3
+
3
32x​+33(−11)​=3x​+3
3
Combine fractions with common denominator
2

3
+
3
(
−
1
1
)
3
=

3
+
3
2
x
3
+
3
(
−
11
)
3
=
x
3
+
3
32x​+33(−11)​=3x​+3
2

+
3
(
−
1
1
)
3
=

3
+
3
2
x
+
3
(
−
11
)
3
=
x
3
+
3
32x+3(−11)​=3x​+3
4
Multiply the numbers
2

+
3
(
−
1
1
)
3
=

3
+
3
2
x
+
3
(
−
11
)
3
=
x
3
+
3
32x+3(−11)​=3x​+3
2

−
3
3
3
=

3
+
3
2
x
−
33
3
=
x
3
+
3
32x−33​=3x​+3
5
Find common denominator
2

−
3
3
3
=

3
+
3
2
x
−
33
3
=
x
3
+
3
32x−33​=3x​+3
2

−
3
3
3
=

3
+
3
⋅
3
3
2
x
−
33
3
=
x
3
+
3
⋅
3
3
32x−33​=3x​+33⋅3​
6
Combine fractions with common denominator
2

−
3
3
3
=

3
+
3
⋅
3
3
2
x
−
33
3
=
x
3
+
3
⋅
3
3
32x−33​=3x​+33⋅3​
2

−
3
3
3
=

+
3
⋅
3
3
2
x
−
33
3
=
x
+
3
⋅
3
3
32x−33​=3x+3⋅3​
7
Multiply the numbers
2

−
3
3
3
=

+
3
⋅
3
3
2
x
−
33
3
=
x
+
3
⋅
3
3
32x−33​=3x+3⋅3​
2

−
3
3
3
=

+
9
3
2
x
−
33
3
=
x
+
9
3
32x−33​=3x+9​
8
Multiply all terms by the same value to eliminate fraction denominators
2

−
3
3
3
=

+
9
3
2
x
−
33
3
=
x
+
9
3
32x−33​=3x+9​
3
⋅
2

−
3
3
3
=
3
(

+
9
3
)
3
⋅
2
x
−
33
3
=
3
(
x
+
9
3
)
3⋅32x−33​=3(3x+9​)
9
Cancel multiplied terms that are in the denominator
3
⋅
2

−
3
3
3
=
3
(

+
9
3
)
3
⋅
2
x
−
33
3
=
3
(
x
+
9
3
)
3⋅32x−33​=3(3x+9​)
2

−
3
3
=

+
9
2
x
−
33
=
x
+
9
2x−33=x+9
10
Add
3
3
33
33
to both sides of the equation
2

−
3
3
=

+
9
2
x
−
33
=
x
+
9
2x−33=x+9
2

−
3
3
+
3
3
=

+
9
+
3
3
2
x
−
33
+
33
=
x
+
9
+
33
2x−33+33=x+9+33
11
Simplify
Add the numbers
Add the numbers
2

=

+
4
2
2
x
=
x
+
42
2x=x+42
12
Subtract

x
x
from both sides of the equation
2

=

+
4
2
2
x
=
x
+
42
2x=x+42
2

−

=

+
4
2
−

2
x
−
x
=
x
+
42
−
x
2x−x=x+42−x
13
Simplify
Combine like terms
Multiply by 1
Combine like terms

=
4
2
x
5 0
2 years ago
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