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3 years ago

Covert 50% into a decimal

Mathematics

1 answer:

BigorU [14]3 years ago

3 0

Converting From Percent to Decimal

When we divide 50 by 100 we get 0.5 (a decimal number).

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What is the slope of the line that passes through the points (2,1) and (5,6)

dlinn [17]

Answer:

5/3

Step-by-step explanation:

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2 years ago

Can you help me find x/5+7=16 Because I don’t know what it is.

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Add the same term to both sides of the equation

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3 years ago

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Dmitry_Shevchenko [17]

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2 years ago

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please show on graph (with x and y coordinates) state where the function x^4-36x^2 is non-negative, increasing, concave up

babunello [35]

Answer:

$y'' =12x^2 -72=0$

And solving we got:

$x=\pm \sqrt{\frac{72}{12}} =\pm \sqrt{6}$

We can find the sings of the second derivate on the following intervals:

$(-\infty$ Concave up

$x=-\sqrt{6}, y =-180$ inflection point

$(-\sqrt{6}$ Concave down

$x=\sqrt{6}, y=-180$ inflection point

$(\sqrt{6}$ Concave up

Step-by-step explanation:

For this case we have the following function:

$y= x^4 -36x^2$

We can find the first derivate and we got:

$y' = 4x^3 -72x$

In order to find the concavity we can find the second derivate and we got:

$y'' = 12x^2 -72$

We can set up this derivate equal to 0 and we got:

$y'' =12x^2 -72=0$

And solving we got:

$x=\pm \sqrt{\frac{72}{12}} =\pm \sqrt{6}$

We can find the sings of the second derivate on the following intervals:

$(-\infty$ Concave up

$x=-\sqrt{6}, y =-180$ inflection point

$(-\sqrt{6}$ Concave down

$x=\sqrt{6}, y=-180$ inflection point

$(\sqrt{6}$ Concave up

8 0

2 years ago

See attached photo below

Daniel [21]

Answer:

Library 2 charges more for each book loaned.
Library 1 has a cheaper subscription fee.

Step-by-step explanation:

Based on the table, we can write the equation for the cost of borrowing from Library 2 using the two-point form of the equation of a line:

y = (y2 -y1)/(x2 -x1)(x -x1) +y1

for (x1, y1) = (2, 15.50) and (x2, y2) = (8, 26) this equation becomes ...

y = (26 -15.50)/(8 -2)(x -2) +15.50 . . . . . fill in the values

y = (10.50/6)(x -2) +15.50 . . . . . . . . . . . . simplify a bit

y = 1.75x -3.50 +15.50 . . . . . . simplify more

In the above, we have x = number of books; y = cost. We can use "n" and "C" for those, respectively, as in the equation for Library 1. Then the monthly cost for Library 2 is ...

C = 12 + 1.75n . . . . . . . arranged to the same form as for Library 1

_____

Now, we can answer the questions.

Library 2 charges more for each book loaned. (1.75 vs 1.50 for Library 1)

Library 1 has a cheaper subscription fee. (10 vs 12 for Library 2)

_____

The numbers in the cost equations are ...

C = (subscription fee) + (cost per book loaned)·n

8 0

3 years ago