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Kay [80]
4 years ago
9

Normal probability plots indicate that the sample data come from normal populations. Are the requirements to use the​ one-way AN

OVA procedure​ satisfied?
Mathematics
1 answer:
Mrrafil [7]4 years ago
4 0

Answer:

No it is not satisfied

Step-by-step explanation:

The one-way ANOVA is used to measure whether the difference between the means of two independent groups are statistically significant.

For it to be satisfied, there has to be one independent variable which is categorical and one dependent variable. The dependent variable on its own has to be a continuous variable

The assumptions are:

1. Equal variance between population

2. Independence between observations

3. The random samples have to be gotten from a normal population.

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Simplify the expression 1.8-0.2x equallys -1.6. Step by step plzzz I will give you 100 points
posledela

1.8 - 0.2x = -1.6         Subtract 1.8 on both sides

1.8 - 1.8 - 0.2x = -1.6 - 1.8

-0.2x = -3.4        Divide -0.2 on both sides

\frac{-0.2x}{-0.2}=\frac{-3.4}{-0.2}

x = 17

3 0
3 years ago
Evaluate the following expression. y + 9 when y = 12
tino4ka555 [31]

Answer:

21

Step-by-step explanation:

y+9 = ?

y=12

12+9=21

5 0
3 years ago
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Which of the following represents a geometric sequence?
Leto [7]
The answer is A

1/4, 1/4, 1/4, 1,4...
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3 years ago
Ray BD is the angle bisector of Given that D<br> Om m-ABD=42<br> m-ABD=21<br> Om ABD=96"
djverab [1.8K]
Om ABD = 96” is the answer
6 0
3 years ago
The lengths of nails produced in a factory are normally distributed with a mean of 3.34 centimeters and a standard deviation of
Shtirlitz [24]

Answer:

3.47 and 3.21

Step-by-step explanation:

Let us assume the nails length be X

X \sim N(3.34,0.07^2)

Value let separated the top 3% is T and for bottom it would be B

P(X < T)= 0.97

Now converting, we get

P(Z < \frac{T-3.34}{0.07})= 0.97

Based on the normal standard tables, we get

P(Z < 1.881)= 0.97

Now compare these two above equations

\frac{T-3.34}{0.07} = 1.881 \\\\ T = 1.881 \times 0.07 + 3.34 \\\\ = 3.47

So for top 3% it is 3.47

Now for bottom we applied the same method as shown above

P(Z < \frac{B-3.34}{0.07})= 0.03

Based on the normal standard tables, we get

P(Z < -1.881)= 0.03

Now compare these two above equations

\frac{B-3.34}{0.07} = -1.881

= -1.881 \times 0.07 + 3.34 \\\\ = 3.21

hence, for bottom it would be 3.21

7 0
3 years ago
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