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Romashka-Z-Leto [24]
3 years ago
5

Time sensitive question. Find the sum of the first 26 terms of an arithmetic series whose first term is 7 and 26th term is 93.

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
7 0

ANSWER

S_{26}=1300

EXPLANATION

The sum of an arithmetic sequence whose first term and last terms are known is calculated using

S_{n}= \frac{n}{2} (a + l)

From the given information, the first term of the series is

a = 7

and the last term of the series is

l = 93

The sum of the first 26 terms is

S_{26}= \frac{26}{2} (7 + 93)

S_{26}= 13 (100)

S_{26}=1300

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here are approximately 3.6 million births in a country each year. Find the birth rate in units of births per minute.
Hatshy [7]

Answer:

6.8 approximately 7 births/mins

Step-by-step explanation:

3600000/525600

If we have 3600000 births in a year, and in a year we have 6omin * 24hrs*365days a year we therefore, have the equation below

Amount of births in a year / (amount of mins in a year)

= 6.8births per mins

3 0
3 years ago
Please help asap, hghhfthbh
ANEK [815]

Answer:

90

Step-by-step explanation:

both sides are equal

both sides have to match

therefore y is 90 and x is 30

it is a symmetry thing

4 0
3 years ago
Read 2 more answers
Please help!!<br><br>Find BD​
Temka [501]

Answer:  8\sqrt{2}

==========================================================

Work Shown:

Focus entirely on triangle ABD (or on triangle BCD; both are identical)

The two legs of this triangle are AB = 8 and AD = 8. The hypotenuse is unknown, so we'll say BD = x.

Apply the pythagorean theorem.

a^2 + b^2 = c^2\\\\c = \sqrt{a^2 + b^2}\\\\x = \sqrt{8^2 + 8^2}\\\\x = \sqrt{2*8^2}\\\\x = \sqrt{8^2*2}\\\\x = \sqrt{8^2}*\sqrt{2}\\\\x = 8\sqrt{2}\\\\

So that's why the diagonal BD is exactly 8\sqrt{2}\\\\ units long

Side note: 8\sqrt{2} \approx 11.3137

6 0
3 years ago
A shopkeeper marked the price of an article a certain percent above the cost price and he allowed 16% discount to make 5% profit
zhuklara [117]

Answer:

25%

Step-by-step explanation:

let the MP be x

sp without vat =x-16%of x

= 21x/25

sp with VAT = 21x/25 +13% of 21x/25

rs 9492 = 2373x/2500

( 9492*2500)/2373=x

x = 10000

cp = ((21x/25 )*100)/100+5 ( 5= profit percent )

=8000

(10000-8000)×100%/8000

=25%

7 0
3 years ago
A local hamburger shop sold a combined total of 659 hamburgers and cheeseburgers on Sunday. There were 50 fewer cheeseburgers so
NISA [10]

Answer:

The sold 354.5 hamburgers and 300.5 cheeseburgers.

Step-by-step explanation:

Let number of hamburgers=h

Let number of cheeseburgers=c

On Sunday, the shop sold a combined total of 659 hamburgers and cheeseburgers. Therefore:

h+c=659....(I)

There were 50 fewer cheeseburgers sold than hamburgers .

c=h-50.....(ii)

Substitution of equation (ii) into (I)

h+(h-50)=659

2h=659+50

2h=709

h=709/2=354.5

From (ii)

c=h-50

=354.5-50=300.5

The sold 354.5 hamburgers and 300.5 cheeseburgers.

NOTE: These result are from the given data. However, we were not informed if the shop sells half burgers or not

7 0
3 years ago
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