Hello AljakeVillena!

You pull horizontally on a 50-kg crate with a force of 450 n and the friction force on the crate is 250 n. the acceleration of the crate is ?

Given,
- mass of crate = 50 kg
- Force you pull it with = 450 N
- Frictional force = 250 N
- Acceleration = ?
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Let's first find the total force/net force acting on the crate. The total force will be :-
- 450 N - 250 N = <u>2</u><u>0</u><u>0</u><u> </u><u>N.</u>
We subtracted the forces because both the forces act on opposite directions.
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Now, let's find the acceleration of the crate. To find the acceleration we must divide the net force by the mass. So,..
- Acceleration = Force/mass
- a = F/m
- a = 200/50
- <u>a = 4 m/s²</u>
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So, the acceleration of the crate is <u>4</u><u> </u><u>m/</u><u>s²</u><u>.</u>
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Hope it'll help you!
ℓu¢αzz ッ
Answer:
the answer is A
Step-by-step explanation:
I have a feeling in my genitals
Answer:
4x2 + 3x + 4
Step-by-step explanation:
Step-1 : Multiply the coefficient of the first term by the constant 4 • 4 = 16
Step-2 : Find two factors of 16 whose sum equals the coefficient of the middle term, which is 3 .
-16+-1=-17
-8+-2=-10
-4+-4=-8
-2+-8=-10
-1+-16=-17
1+16=17
2+8=10
4+4=8
8+2=10
16+1=17
Final result :
4x2 + 3x + 4
No error - A and B are completely right, and using the subtraction law D is right
Let's see here... well, since the first letter in the ratio is from the first triangle, then, the first one in the equal ratio is going to have to be that as well, and the ratio of c:a wouldn't work, since c was already used. By process of elimination, it's gotta be b:q.