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Anastaziya [24]
3 years ago
14

Which value is the solution to the equation -8 = 6 - 7x? A. -7 B. - 2 C. 2 D. 5​

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
8 0

Step-by-step explanation:

the answer is c: 2..............

You might be interested in
A car is traveling at a speed of miles per hour. What is the car's speed in kilometers per hour? How many kilometers will the ca
mihalych1998 [28]

Complete Question:

As you may have intentionally forgotten to mention the important data elements in your question like at what rate a car is travelling and number of hours car will travel in required number of miles etc. After a little research it seems I have found the complete question you were supposed to write. Hence, I am answering based on this complete question, but anyways, it would certainly improve your concept. Here is the complete question:

<em>A car is traveling at a rate of 60 kilometers per hour. What is the car's rate in miles per hour? How many miles will the car travel in 4 hours? In your computations, assume that 1 mile is equal to 1.6 kilometers. Do not round your answers.</em>

<em>Answer:</em>

The car will travel 37.5 miles in one hour.

The car travel 150 miles in 4 hours.

<em>Fetching data from Question:</em>

The rate at which car is traveling: 60 kilometers per hour

one mile = 1.6 km

<em>a) How many miles a car will travel in one hour?</em>

<em>b) How many miles will the car travel in 4 hours?</em>

<em>Calculation:</em>

<em>a) How many miles a car will travel in one hour?</em>

As one mile is equal to 1.6 km.

The rate at which car is traveling: 60 kilometers per hour

So, just divide 60 with 1.6 to get in miles

                      i.e. 60/1.6 = 37.5 miles per hour  

So, the car will travel 37.5 miles in one hour.

<em>b) How many miles will the car travel in 4 hours?</em>

As the car will travel 4 hours.

And car travels 37.5 miles in one hour

So, just multiply the number of hours i.e. 4 with the miles in one hour (speed) i.e. 37.5 to calculate the distance in 4 hours. So,

                                 The distance =  speed × time

                                                        =  37.5  × 4

                                                        =  150 miles

So, the car travel 150 miles in 4 hours.

<em />

<em>Keywords: distance, speed, kilometers, miles</em>

<em> learn more about distance travel and speed from brainly.com/question/12580265 </em>

<em> #learnwithBrainly</em>

4 0
3 years ago
How do you do these problems?
kvv77 [185]
ITS TOO SMALL TO SEE THAT PRINT, BUT  CAN  SOMEONE PLEASE HELP ME ANSWER THIS PROBLEM  ON MY PROFILE I JUST POSTED IT AND NO ONE WILL  HELP ME!!1 
6 0
4 years ago
A 75-gallon tank is filled with brine (water nearly saturated with salt; used as a preservative) holding 11 pounds of salt in so
Debora [2.8K]

Let A(t) = amount of salt (in pounds) in the tank at time t (in minutes). Then A(0) = 11.

Salt flows in at a rate

\left(0.6\dfrac{\rm lb}{\rm gal}\right) \left(3\dfrac{\rm gal}{\rm min}\right) = \dfrac95 \dfrac{\rm lb}{\rm min}

and flows out at a rate

\left(\dfrac{A(t)\,\rm lb}{75\,\rm gal + \left(3\frac{\rm gal}{\rm min} - 3.25\frac{\rm gal}{\rm min}\right)t}\right) \left(3.25\dfrac{\rm gal}{\rm min}\right) = \dfrac{13A(t)}{300-t} \dfrac{\rm lb}{\rm min}

where 4 quarts = 1 gallon so 13 quarts = 3.25 gallon.

Then the net rate of salt flow is given by the differential equation

\dfrac{dA}{dt} = \dfrac95 - \dfrac{13A}{300-t}

which I'll solve with the integrating factor method.

\dfrac{dA}{dt} + \dfrac{13}{300-t} A = \dfrac95

-\dfrac1{(300-t)^{13}} \dfrac{dA}{dt} - \dfrac{13}{(300-t)^{14}} A = -\dfrac9{5(300-t)^{13}}

\dfrac d{dt} \left(-\dfrac1{(300-t)^{13}} A\right) = -\dfrac9{5(300-t)^{13}}

Integrate both sides. By the fundamental theorem of calculus,

\displaystyle -\dfrac1{(300-t)^{13}} A = -\dfrac1{(300-t)^{13}} A\bigg|_{t=0} - \frac95 \int_0^t \frac{du}{(300-u)^{13}}

\displaystyle -\dfrac1{(300-t)^{13}} A = -\dfrac{11}{300^{13}} - \frac95 \times \dfrac1{12} \left(\frac1{(300-t)^{12}} - \frac1{300^{12}}\right)

\displaystyle -\dfrac1{(300-t)^{13}} A = \dfrac{34}{300^{13}} - \frac3{20}\frac1{(300-t)^{12}}

\displaystyle A = \frac3{20} (300-t) - \dfrac{34}{300^{13}}(300-t)^{13}

\displaystyle A = 45 \left(1 - \frac t{300}\right) - 34 \left(1 - \frac t{300}\right)^{13}

After 1 hour = 60 minutes, the tank will contain

A(60) = 45 \left(1 - \dfrac {60}{300}\right) - 34 \left(1 - \dfrac {60}{300}\right)^{13} = 45\left(\dfrac45\right) - 34 \left(\dfrac45\right)^{13} \approx 34.131

pounds of salt.

7 0
2 years ago
Find the greatest common factor of these three expressions.
leva [86]
6x

42/6 = 7 (valid), 18/6 = 3 (valid), 12/6 = 2 (valid)

7, 8, 9, 10, and 11 are all not divisible by 12, and 12 is not divisible by 18, so 6 is the highest number.

Also, each number has at least one x, so you can take one out.

Remaining=
6x (7 + 3x^2 + 2x^3)

3 0
3 years ago
PROVING THEOREMS OF SQUAD can someone help me pleasee ASAP​
AfilCa [17]

Answer:

40 units

Step-by-step explanation:

For a square, all the sides are equal and the interior angles are equal and all equal to 90. Hence;

m<BOJ = 90 degrees

m<BOJ = 4x - 6

Equating both to get x;

4x - 6 = 90

4x = 90+6

4x = 96

x = 96/4

x = 24

Since all the sides are equal, hence BO = JO = 2x-8

JO = 2x - 8

Substitute x = 24 into JO

JO = 2(24) - 8

JO = 48 - 8

JO = 40

Hence the measure of JO is 40 units

6 0
3 years ago
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