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Eva8 [605]
3 years ago
14

PLEASE HELP!!!!!!!!!!!!!

Mathematics
1 answer:
Anvisha [2.4K]3 years ago
6 0

Answer:

60.7

Step-by-step explanation:

multiply 7 3/4 by 4, then multiply 4 5/8 by 4, then 2 4/5 by 4, then add it all together to get your answer.

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If f is a scalar field and F, G are vector fields, then f F, F · G, and F × G are defined by the following. (f F)(x, y, z) = f(x
valentina_108 [34]

Answer:

Step-by-step explanation:

Consider curl (fF) where f is a scalar function and F is a vector function

                  F=F_{1}i +F_{2}j +F_{3}k

                     i         j          k                

curl(fF) = \frac{\partial}{\partial x}      \frac{\partial}{\partial y}      \frac{\partial}{\partial z}        

                  fF_{1}    fF_{2}    fF_{3}  

curl(fF)=i(\frac{\partial}{\partial y}(fF_{3})-\frac{\partial}{\partial z}(fF_{2}))-j(\frac{\partial}{\partial x}(fF_{3})-\frac{\partial}{\partial z}(fF_{1}))+k(\frac{\partial}{\partial x}(fF_{2})-\frac{\partial}{\partial y}(fF_{1}))

=i(\frac{\partial}{\partial y}(F_{3})+\frac{\partial}{\partial y}(f)-\frac{\partial}{\partial z}(F_{2})-\frac{\partial}{\partial z}(f))-j(\frac{\partial}{\partial x}(F_{3})+\frac{\partial}{\partial x}(f)-\frac{\partial}{\partial z}(F_{1})-\frac{\partial}{\partial z}(f))+k(\frac{\partial}{\partial x}(F_{2})+\frac{\partial}{\partial x}(f)-\frac{\partial}{\partial y}(F_{1})-\frac{\partial}{\partial y}(f))

curl(fF)=f(\Delta\times F)+(\Delta f)\times F

3 0
3 years ago
Use the table to find the COORDINATES of the image ​
Natasha_Volkova [10]

Answer:

Q = ( -3 , 6 ) .... R = ( -1 , 8 )  ...... S = ( -5 , 7 )

Step-by-step explanation:

Q = ( 1 + ( -4 ) , 4 + 2 ) = ( -3 , 6 )

R = ( 3 + ( -4 ) , 6 + 2 ) = ( -1 , 8 )

S = ( -1 + ( -4 ) , 5 + 2 ) = ( -5 , 7 )

8 0
2 years ago
On a number line what is the distance between -12 and 20 ??
KIM [24]

Answer:  Step-by-step explanation:

In order to answer this question you will need to find 2 distances and then add them to each other.

Begin at -29.  How far will you have to move to the right 29 in order to get to 0?

Now how far will you have to more to get from 0 to 100?

Draw an open number line to help you.

_____________________________________________________

-29                                           0                                                   100

Your first distance is 29.  Your second distance is 100.  The total distance is 129.

3 0
3 years ago
J(–6, 2) and K(3, 2) are the endpoints of the base of an isosceles triangle. Give the x-coordinate of the third vertex.
Korvikt [17]

Answer:

Step-by-step explanation:

If you plot J and K in a coordinate plane, you see that the line formed is a perfectly horizontal line through y = 2.  In order for this triangle to be an isosceles, the third x-coordinate would have to be located midway through the x-coordinates of the base.  The midpoint between the x-coordinates is found by adding the 2 x-coordinates and dividing the sum by 2.  -6+\3 = -3 and -3/2 = -3/2.  So the x-coordinate is -3.2 or -1.5

4 0
3 years ago
Read 2 more answers
Find the area of each composite figure. Use 3.14 for π. Round to the nearest tenth if necessary. Whats the correct label?
GuDViN [60]

Step-by-step explanation:

Square= bh

Square= 2×2=

half-circle = 1/2Pi*r×r

half-circle 2 = 1/2Pi*r×r

We would put 1/2 for the half-circle because its half of a circle. And we square it because where finding area. The middle is square, and the two up top is half a circle. Hope that helps :D

8 0
3 years ago
Read 2 more answers
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