Answer:
24
Step-by-step explanation:
Let total number of the chocolates be x.
25% of x = 6 (because 100 - 75 = 25% of chocolates left).
25/100 x x = 6
x = 600/25
x = 24
Hence, 24 is the total amount of chocolates.
<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em> </em><em>:</em><em>)</em>
Answer:
37.62 degrees + 47.87 degrees = 85.49 degrees
Step-by-step explanation:
For this question we are trying to find the "absolute value" between these 2 numbers, because one of the numbers are negative and the other one is positive, we are going to add both of them together. That is how we got 85.49. In a different equation, we might have done something different.
Answer:
$8,287,429
Step-by-step explanation:
The total profit will be the sum of a geometric series. The formula for that sum is ...
Sn = a1 × (r^n -1)/(r -1)
where a1 is the first term, r is the common ratio, and n is the number of terms.
__
Here, the series has first term $140,000, common ratio 1+0.20 = 1.2, and we want the total of 14 terms. The total profit is ...
S14 = ($140,000) × (1.2^14 -1)/(1.2 -1) ≈ $8,287,429
In the first 14 years of operation, the total profit would be $8,287,429.
Answer:
Part A
x is 46°
Part B
Alternate angles are angles that are in relatively opposite locations relative to a transversal
Please see attached diagram showing alternate angles
Step-by-step explanation:
Part A
∠DRP = 110° (Given)
∠QPA = 64° (Given)
∠QPR =
Given that AB is parallel to CD, we have;
∠DRP is congruent to ∠APR (Alternate angles to a transversal RP of parallel lines AB and CD)
Therefore, ∠APR = 115°
∠APR = ∠QPA + ∠QPR (Angle addition postulate)
∴ 115° = 64° + ∠QPR
∠QPR = 110° - 64° = 46°
x = 46°
Part B.
Given that AB is parallel to CD, the lines common (that intersects) both lines are the transversal lines
The angles formed between the parallel lines and the transversal lines have special relationships based on their position with respect to each other
In the question, the angle 110° given between CD and the transversal RP, is found to at an alternate position to the angle ∠APR between the same transversal RP and AB and given that alternate angles are always equal, angle ∠APR is therefore also equal to 110°.