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2 years ago

8

Connor is constructing parallelogram ABCD. He has plotted A at (−2, 4), B at (0, 3), and D at (−3, 2). Which coordinate could be

the location of point C?
C (0, 0)
C (0, 1)
C (−1, 1)
C (−1, 2)

1 answer:

bezimeni [28]2 years ago

5 0

Answer:

C (-1, 1)

Step-by-step explanation:

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3 years ago

4(3x^2y^4)^3 / (2x^3y^5)^4

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Solving the expressions $\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$ we get $\frac{27}{4x^{6}y^{8}}$

Step-by-step explanation:

We need to Solve the expression: $\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$

Solving:

$\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$

$=\frac{4(3^3x^6y^{12})}{(2^4x^{12}y^{20})}\\=\frac{4(27x^6y^{12})}{(16x^{12}y^{20})}\\=\frac{108x^6y^{12}}{16x^{12}y^{20}}$

Applying exponent rule: $\frac{x^a}{x^b}=x^{a-b}$

$=\frac{108x^{6-12}y^{12-20}}{16}\\=\frac{27x^{-6}y^{-8}}{4}$

Another exponent rule says: $x^{-a}=\frac{1}{x^a}=$

$=\frac{27}{4x^{6}y^{8}}$

So, solving the expressions $\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$ we get $\frac{27}{4x^{6}y^{8}}$

Keywords: Solving Exponents

Learn more about Solving Exponents at:

#learnwithBrainly

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3 years ago

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<h2>Answer: x = -6</h2>

<h3>Step-by-step explanation:</h3>

To solve for x, we have to find a way to make x the subject of the equation (get x on one side and everything else on the other side)

<h3></h3>

since -4 = (2/3)x [mutiply both sides by 3]

⇒ -4 × 3 = 2x [divide both sides by 2]

⇒ (-12/2) = x [simplify by dividing -12 by 2]

∴ x = -6

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2 years ago

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