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Zanzabum
3 years ago
6

Save me from my nightmare odds

Mathematics
1 answer:
Natalka [10]3 years ago
3 0

Answer:

Why am i doing the same exact thing lol

Step-by-step explanation:

You might be interested in
Which of the following shows that polynomials are closed under addition when two polynomials 4x2 − 8x − 7 and −5x + 16 are added
Artyom0805 [142]
First we have to combine like terms. 4x² is one term. -8x is another term. -7 is another term. poly = "many" ⇒ polynomial = many terms

(4x² - 8x - 7) + (-5x + 16)

4x² - 8x - 7 - 5x + 16

Combine like terms.
Step 1: 4x² has no other terms with x² so it stays by itself.
Step 2: -8x and -5x are like terms because they both have x.
So -8x -5x = -13x (You put two negatives together)
Step 3: -7 and 16 don't have any x with them. -7 + 16 = 16 - 7 = 9

Now we put all the answers of the steps together.
Step 1: 4x²
Step 2: -13x
Step 3: 9

So the answer is 4x² - 13x +9
And it's a polynomial because there are three terms = "more than one term"

4 0
4 years ago
-7x-3x+2=-8x-2 can you please show your work how
iVinArrow [24]

Answer:

x = 2

Step-by-step explanation:

Given

- 7x - 3x + 2 = - 8x - 2 ← simplify left side

- 10x + 2 = - 8x - 2 ( add 8x to both sides )

- 2x + 2 = - 2 ( subtract 2 from both sides )

- 2x = - 4 ( divide both sides by - 2 )

x = 2

8 0
4 years ago
Let X be the future lifetime random variable in years for a newborn (age 0). The probability density function of X is as follows
meriva

Answer:

0

Step-by-step explanation:

First we need to find the value of constant k in equation. To find k we use the formula:

\int\limits^{100}_0 {ke^{-0.01x}} \, dx =1\\Integrating:\\k\int\limits^{100}_0 {e^{-0.01x}} \, dx =1\\\frac{k}{-0.01}[e^{-0.01x}]_0^{100}=1\\-100k [e^{-0.01x}]_0^{100}=1\\-100k[e^{-0.01*100}-e^{-100*0}]=1\\-100k[e^{-1}-e^0]=1\\-100k(-0.632)=1\\63.2k = 1\\k=0.0158

the probability that a person age 20 will live for at least 20 more years = P(40 ≤ x <∞).

The person would live for at least 40 years

Therefore:

P(40 ≤ x <∞) =

\int\limits^{\infty}_{40} 0.0158e^{-0.01x}} \, dx \\Integrating:\\0.0158\int\limits^{\infty}_{40} {e^{-0.01x}} \, dx =\frac{0.0158}{-0.01}[e^{-0.01x}]_{40}^{\infty}\\=-1.58 [e^{-0.01x}]_{40}^{\infty}=-1.58[e^{-\infty}-e^{-100*40}]\\=-1.58[e^{-\infty}-e^{-4000}]=-1.58(0-0)=0

6 0
3 years ago
Sixty people are invited to a party
natka813 [3]

Answer:

Need more information. What do you mean "Sixty people are invited to a party" ?

Step-by-step explanation:

5 0
4 years ago
Read 2 more answers
Rewrite the equation in logarithmic form: 4^3 = 64
storchak [24]
4^3 = 64

log4 64 = 3

The exponent always comes to the other side.
8 0
3 years ago
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