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4 years ago

9

What is the pattern as the exponents decrease?

1 answer:

Nana76 [90]4 years ago

4 0

Can we see the patern please

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You are ordering a pizza. You have a choice of three toppings: mushrooms, pepperoni, and peppers. How many different pizzas can

astra-53 [7]

U can do exactly 6 different pizzas

8 0

4 years ago

Read 2 more answers

soldi70 [24.7K]

Write a C program to compute Matrix Multiplication of two matrices. Use one dimensional array to store each matrix, where each row is stored after another. Hence, the size of the array will be a product of number of rows times number of columns of that matrix. Get number of row and column from user and use variable length array to initialize the size of the two matrices as well as the resultant matrix. Check whether the two matrices can be multiplied or not. Write a getMatrix() function to generate the array elements randomly. Write a printMatrix() function to print the 1D array elements in 2D Matrix format. Also, write another function product(), which multiplies the two matrices and stores in the resultant matrix. With SEED 5, the following output is generated.

Sample Output

Enter the rows and columns of Matrix A with space in between: 3 5

Enter the rows and columns of Matrix B with space in between: 5 4

Matrix A:

8 6 4 1 6

2 9 7 7 5

1 3 1 1 2

Matrix B:

9 5 4 5

9 9 8 1

4 4 3 5

2 6 2 1

4 5 2 4

Product AxB:

168 146 106 91

161 186 125 81

50 52 37 22

In conclusion, the answer is 5x1

Please give Brainliest answer thanks! :)

6 0

4 years ago

Read 2 more answers

Evaluate the following: 6+ (5 + 1).

Vsevolod [243]

6+(5+1)
(5+1)=6
6(6)
6x6= 36

3 0

3 years ago

Read 2 more answers

Find the solution set of this inequality|10x+20| ≤10

Pavlova-9 [17]

Answer:

solution is

[-3,-1]

Step-by-step explanation:

we are given

$|10x+20|\leq 10$

Firstly, we will find critical values

so, let's assume it is equal

$|10x+20|= 10$

now, we can break absolute sign

For $|10x+20|= -(10x+20)$ :

$-(10x+20)= 10$

we can solve for x

$-10x-20= 10$

Add both sides by 20

$-10x-20+20= 10+20$

$-10x= 30$

Divide both sides by -10

and we get

$x=-3$

For $|10x+20|= (10x+20)$ :

$(10x+20)= 10$

we can solve for x

$10x+20= 10$

Subtract both sides by 20

$10x+20-20= 10-20$

$10x= -10$

Divide both sides by 10

and we get

$x=-1$

so, critical values are

$x=-3$

$x=-1$

now, we can draw a number line and locate these values

and then we can check inequality on each intervals

For $(-\infty,-3)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-5

$|10\times -5+20|\leq 10$

$|-50+20|\leq 10$

$30\leq 10$

so, this is FALSE

For $[-3,-1]$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-2

$|10\times -2+20|\leq 10$

$|-20+20|\leq 10$

$0\leq 10$

so, this is TRUE

For $(-1,\infty)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=0

$|10\times 0+20|\leq 10$

$|0+20|\leq 10$

$20\leq 10$

so, this is FALSE

so, solution is

[-3,-1]

7 0

3 years ago

Is this true or false? Ill give brainliest :)

jeyben [28]

False

A function can’t have 2 y-intercepts so y is not a function of x

7 0

3 years ago