8 - 11 = -3. The square root of 25/121 = (the square root of 25) / (the square root of 121) = 5/11 . -3 x 5/11 = -3/1 x 5/11 = (-3 x 5) / (1 x 11) = (-15)/11 = -15/11.
You do Y2-Y1 Divided by X2-X1
The closest to the maximum number of cups the punch bowl can hold is 30
<h3>How to determine the number of cups?</h3>
The given parameters are:
1 cup = 15 cubic inches
Diameter of bowl, d = 12 inches
The radius is the half of the diameter.
So, we have:
r = 6
The volume of the bowl is then calculated using:

This gives

Evaluate
V = 452.16
The maximum number of cups is then calculated using:
Cups = 452.16/15
Evaluate
Cups = 30.1444
Approximate
Cups = 30
Hence, the closest to the maximum number of cups the punch bowl can hold is 30
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200*(107%)^x
x is the number of quarters that passed.
each year has 4 quarters, so 12 yaers would have: 12*4 = 48 quarters
200*(107%)^48 = 5146
Answer:
kk ill save ya from the scary question
the answer is B
Because the original picture is 16 by 20...but the scaled down picture is 4 by 5. Multiply 16 and 20 respectively by 1/4, and you get the scaled version that is 4 by 5