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alexira [117]
4 years ago
12

Caroline won $250,000 in a lottery. After paying $96,000 in taxes, she placed the remaining amount in a savings account at a 2%

interest rate. How much interest will the account earn after just 6 months?
Mathematics
1 answer:
Serjik [45]4 years ago
5 0

Answer:

18,480

Step-by-step explanation:

Ⓗⓘ ⓣⓗⓔⓡⓔ

Well, first, you would fine how much she put in the bank in the first place!

250,000-96,000=154,000

Then you would do 154,000*0.02 to find how much interest is charged per month.

154,000*0.02=3080

Finally, you would multiply 3080 by 6 {because you need to account for all of the months}.

3080*6=18,480

(っ◔◡◔)っ ♥ Hope this helped! Have a great day! :) ♥

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Joanna has been saving for retirement for 40 years. She made monthly deposits of $275 and earned 5.6% annual interest, compounde
ryzh [129]

Joanna deposited $132000 and her interest amount is $359730.35

<u>Step-by-step explanation:</u>

Monthly deposit = $275

Interest = 5.6%

Time = 40 years

After 40 years her account balance = $491730.35

If she deposit $275 monthly then after 40 years she will have deposited ,

= 275 x 12 x 40

= $132000

The remaining is her interest amount.

Interest amount = 491730.35 - 132000

= $359730.35

Joanna deposited $132000 and her interest amount is $359730.35

6 0
3 years ago
Estimate the percent of each number. 47% of 77
Anettt [7]

ANSWER

36 .19

EXPLANATION

We want to estimate

47\% \: of \: 77

This is the same as

\frac{47}{100}  \times 77

or

\frac{47}{100} \times  \frac{77}{1}

We multiply the numerators to get,

\frac{3619}{100}

We convert to decimals to get

36.19

5 0
3 years ago
Ten pounds of mixed birdseed sells for 8.24 per pound. The mixture is obtained from two kinds of birdseed, with one variety pric
Kipish [7]

Answer:

2 pounds of 1st kind and 8 pounds of 2nd kind are mixed.

Explanation:

Given:

Ten pounds of mixed birdseed sells for 8.24 per pound.  

Price of the 1st variety of birdseed=5.68 per pound

Price of the 2nd variety of the birdseed=8.88 per pound.  

To find :

Pounds of 1st variety of birdseed are used in the mixture=?

Pounds of 2ndvariety of birdseed are used in the mixture=?

Solution:

Let the weight of 1st kind added in mixture be n pounds.

Then weight of 2nd kind will be 10 – n pounds.

Now, total cost of mixture = cost of 1st kind birdseed + cost of 2nd kind birdseed

Weight of mixture x cost per pound = weight of 1st kind x cost per pound + weight of 2nd kind x cost per pound.

Substituting the values,

10\times8.24 = n\times5.68 + (10-n)\times8.88

82.4 = 5.68n + 88.8 – 8.88n  

8.88n – 5.68n = 88.8 – 82.4  

3.2n = 6.4  

n = \frac{3.2}{6.4}

n = 2

Then, weight of 2nd kind is 10 – 2 = 8 pounds.

Hence, 2 pounds of 1st kind and 8 pounds of 2nd kind are mixed.

5 0
3 years ago
What is the Mode of the following data set of 2 , 4, 5 ,6 ,7 ,3 ?
disa [49]

The mode of any data set is the number that appears most often.

In this case, no number appears more often than another.

In this data set, there is no mode.

7 0
3 years ago
Read 2 more answers
– 4/5 (9x – 20) – 3x = 4/5 x – 6. Enter the value of x that makes this equation true.
marta [7]
- 4/5*9x +4/5*20 - 3x= 4/5x- 6
-36/5*x+16-3x-4/5*x= -6
-36/5*x-15x/5-4/5*x=-6-16
-55/5*x=-22
-11x= -22
x= -22:(-11)
x=2

-4/5(9*2-20)-3*2=4/5*2-6
-4/5*(-2)-6=8/5-6
8/5-6=8/5-6
4 0
3 years ago
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