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2 years ago

Pls help! who ever solves first will be awarded brainiest!!! solve asap!

Mathematics

2 answers:

Kipish [7]2 years ago

8 0

Answer:

Step-by-step explanation:

Lostsunrise [7]2 years ago

7 0

Answer:

[ ] = 3¹³

Step-by-step explanation:

3¹⁷ - 3¹⁵ + 3¹³ = [ ] x 73

3¹³ [3⁴ - 3² + 1] = [ ] x 73

3¹³ [81 - 9 + 1] = [ ] x 73

3¹³ x 73 = [ ] x 73

[ ] = 3¹³ [It says 3^13 if it is not clear/visible]

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( x + 3 )( y + 2 ) = xy - 5 ( x + 2 )( y - 3 ) = xy

Paraphin [41]

Answer:

xy+2x+3y+6=xy-5 .............(1)

xy-3x+2y-6=xy.....,.,(2)

2x+3y=-11

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(2)*(2x+3y)=-11

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2 years ago

What is the equation of this parabola in vertex form

attashe74 [19]

first off, let's notice the parabola is a vertical one, therefore the squared variable is the x, and the parabola is opening upwards, meaning the coefficient of x² is positive.

let's notice the vertex, or U-turn, is at (-2, 2)

$\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} \boxed{y=a(x- h)^2+ k}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{-2}{ h},\stackrel{2}{ k}) \\\\\\ y=+1[x-(-2)]^2+2\implies y=(x+2)^2+2$

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3 years ago

In a survey at a local college, 18% of students reported that they do not own a mobile device with internet capabilities. if 20

Sholpan [36]

Answer:

0.64

Step-by-step explanation:

The probability that randomly selected student doesn't own a mobile device with internet capabilities is $p=0.18$ and the probability that randomly selected student owns a mobile device with internet capabilities is $q=1-p=1-0.18=0.82.$

If 20 students are selected at random, the probability that at most 5 students (0 students, 1 student, 2 students, 3 students, 4 students or 5 students) don't own a mobile device with internet capabilities is

$Pr=C_{20}^0p^0q^{20}+C_{20}^1p^1q^{19}+C_{20}^2p^2q^{18}+C_{20}^3p^3q^{17}+C_{20}^4p^4q^{16}+C_{20}^5p^5q^{15}=q^{20}+20pq^{19}+190p^2q^{18}+1,140p^3q^{17}+4,875p^4q^{16}+15,504p^5q^{15}\approx 0.6405021423\approx 0.64.$

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3 years ago

A cube with side length 4p is stacked on another cube with side length 2q^2. What is the total volume of the cubes in factored f

inysia [295]

Volume of the cube with side 4p = 4p x 4p x 4p = 64p³

Volume of the cube with side 2q² =  2q² x  2q² x  2q² = 8q⁶

Total Volume = 64p³ +  8q⁶

Total Volume = (4p)³ + (2q²)³

Total Volume = (4p + 2q²)( ( 4p)² - (4p)(2q²) + (2q²)²)

Total Volume = (4p + 2q²)( 16p² - 8pq² + 4q⁴)

Answer:  (4p + 2q²)( 16p² - 8pq² + 4q⁴)

7 0

3 years ago

Read 2 more answers

Is the question a statistical question? (Yes/No) How many miles is your house from school?

Kisachek [45]

No, the question is not a statistical question.

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2 years ago