Answer:
Actually it's not polygon. it's a nonagon. With r=8.65mm″, the law of cosines gives us side a:
a=√{b²+c²−2bc×cos40°}
a=√{149.645−149.645cos40°}
Area Nonagon = (9/4)a²cos40°
=9/4[149.645−149.645cos40°]cot20°
=336.70125[1−cos(40°)]cot(20°)
Applying an identity for the cos(40°) does not get us very far…
= 336.70125[1−(cos2(20°)−1)]cot(20°)
= 336.70125[2−cos2(20°)]cot(20°)
= 336.70125[2−(1−sin2(20°))]cot(20°)
= 336.70125[1+sin2(20°)]cos(20°)sin(20°)
= 336.70125[cot(20°)+sin(20°)cos(20°)]mm²
Answer:
101in
Step-by-step explanation:
9*5=45
9*4=36
5*4=20
45+36+20=101
Answer:
sqrt 50
Step-by-step explanation:
First of all this is a square so if AB = 5, then AD is also 5.
Let's get rid of the other triangle and only focus on triangle ABD.
Using Pythagorean theorem we are able to solve this problem.
The Pythagorean Theorem basically states that:
a^2 + b^2 = c^2
Where a and b are the legs and c is the hypotenuse, aka the thing that we are trying to solve for right now.
Substitute these numbers in: 5^2 + 5+2 = c^2
Solve: 50 = c^2
c= sqrt 50
^ and that is our answer!
Answer:
B.!
Step-by-step explanation:
HAVE AN SUPER DAY!
