What is a + a^2 ?<br> Thank you<br> Don't write the steps, just the answer

The Lupu Bridge in China is 12,795 ft long. The Hart Bridge in the USA is 3,845 ft long. About how much longer is the Lupu Bridg

AleksAgata [21]

You subtract the length of the Lupu Bridge by the length of thee Hart Bridge after you round them to the nearest thousandth and you get your final answer!
12,795 -> 13,000
3,845 -> 4,000
13,000 - 4,000 = your answer

4 0

3 years ago

Salt cost 40cents for every 100 grams. how many grams of salt can be bought with$2?

Leona [35]

Answer:

500 Grams

Step-by-step explanation:

40 x 5 = 200 = $2

100 x 5 = 500

3 0

3 years ago

Read 2 more answers

Which measurement is the best estimate for the mass of a penny?

Maksim231197 [3]

B is correct - 2.5g :)

8 0

4 years ago

Please Help Me ASAP.

Evgesh-ka [11]

Answer:

Step-by-step explanation:

If y= x + 4 then plug it into the other equation where the y is. So 5x + x +4=22. Then solve.

for x for y

5x + x + 4=22 y=x +4

6x+4=22 y=3+4

22-4=18 y=7

6x = 18

18/6=3

x=3 so, x=3 and y=7

7 0

3 years ago

A rectangular parking lot has an area of 315 square yards. The width of the parking lot is 5 yards longer than the length of the

Blababa [14]

Answer:

Dimension of parking lot is approximately 15.425 × 20.425 yards.

Step-by-step explanation:

Given:

Area of the parking lot = $315 \ yd^2$

Let the length of the parking lot be $'l'$

Also Given:

The width of the parking lot is 5 yards longer than the length of the parking lot.

so we can say that;

width of the parking lot, $w=5+l$

We need to find the dimension of parking lot.

Solution:

Now we can say that;

Area of rectangle is equal to length times width.

framing in equation form we get;

$lw=315$

Now substituting the value of w in above equation we get;

$l(l+5)=315\\\\l^2+5l=315\\\\l^2+5l-315=0$

Now we will find the roots using quadratic equation.

$ax^2+bx+c =0$

a = 1

b=5

c=-315

Formula for quadratic equation is;

$l =\frac{-b\±\sqrt{b^2-4ac}}{2a}$

First we will find;

$\sqrt{b^2-4ac} = \sqrt{5^2-4\times1\times-315} =\sqrt{25+1260}=\sqrt{1285} \approx35.85$

Now we will substitute the value we get;

$l =\frac{-5\±35.85}{2\times1}= \frac{-5\±35.85}{2}$

Now we will find 2 roots we get;

$l= \frac{-5+35.85}{2}= \frac{30.85}{2}\approx15.425\\\\OR\\\\l =\frac{-5-35.85}{2}= \frac{-40.85}{2} \approx -20.425$

Now we get 2 values of length one is positive and other is negative.

But length of parking lot cannot be negative hence we will discard the negative value.

Hence the length of the parking lot = 15.425 yards

Width of the rectangular parking lot = $l+5=15.425+5 =20.425$

Hence we can say that dimension of parking lot is approximately 15.425 × 20.425 yards.

3 0

3 years ago

What is a + a^2 ? Thank you Don't write the steps, just the answer