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sergij07 [2.7K]
3 years ago
15

Find the difference (6y3 + 17y - 3) - (4y3-11y+9)

Mathematics
2 answers:
mafiozo [28]3 years ago
7 0
Your correct answer is: 2y^3+28y-12
 Let's simplify step-by-step. 6y3+17y−3−(4y3−11y+9)
Distribute the Negative Sign:
=6y3+17y−3+−1(4y3−11y+9)
=6y3+17y+−3+−1(4y3)+−1(−11y)+(−1)(9)
=6y3+17y+−3+−4y3+11y+−9
Combine Like Terms:
=6y3+17y+−3+−4y3+11y+−9
=(6y3+−4y3)+(17y+11y)+(−3+−9)
 =2y3+28y+−12
Answer: =2y3+28y−12
Genrish500 [490]3 years ago
5 0
(6y3 + 17y - 3) - (4y3 - 11y + 9) =

Answer: 2y^3 + 28y - 12
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Answer:

A

Step-by-step explanation:

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5 0
3 years ago
Find p(-4) and p(2) for the function p(x)=11x^5-11x^4-5x^2+15x-8
egoroff_w [7]

hi,

you must replace x by the number between parenthese.

I show you with the first one and let you do the second one

p(x) = 11x^5 -11x^4 - 5x^2 +15x-8

p(-4)  =   11 (-4)^5 - 11 (-4)^4 -5(-4)² +15(-4) -8

p(-4) =     11  ( -1024- 256) - 5*16 -60-8

p(-4) =   11 ( -1280) -80-60-8

p(-4)   =    - 14080 - 148

p(-4) =   - 14 228

7 0
3 years ago
Which functions domain consists of all real numbers except -2?
Eddi Din [679]

Answer:

option (a) f(x)= 1/x+2

Step-by-step explanation:

(a) f(x) = 1/ x+2

To find the restriction for domain , we set the denominator =0  and solve for x

x+2 =0, so x=-2

When x=-2  then denominator becomes 0 that is undefined.

So, domain is all real numbers except -2

(b) f(x)= 2x

In this function, there is no denominator or square root or log function

so there is no restriction for x, hence domain is all real numbers

(c) f(x) = 2x-2

In this function, there is no denominator or square root or log function

so there is no restriction for x, hence domain is all real numbers

f(x) = 1/ sqrt(x+2)

if we have square root in the denominator then we set the denominator >0 and solve for x. because square root of negative values are undefined

x+2>0, x>-2

Hence domain is all real numbers that are greater than -2

8 0
3 years ago
Helpppppppppp me plz
creativ13 [48]
X+6 > -18+9x
18+6 > 8x
24 > 8x
3 > x
5 0
2 years ago
two brothers marco and fernando are training for a marathon marco runs at a rate of 6miles per hor. Fernando funs at at a rate o
satela [25.4K]
We know that
speed=distance/time
solve for time
time=distance/speed

in this problem
<span>Marco runs at a rate of 6 miles per hour. 
</span><span>Fernando funs at a rate of 7.2 miles per hour
Difference=7.2-6=1.2 miles/hour
so
speed=1.2 miles/hour
distance=0.3 miles
time=?
</span>time=distance/speed-----> 0.3/1.2-----> 0.25 hour-----> 0.25*60=15 minutes
<span>
the answer is
0.25 hour (15 minutes)

Alternative Method
Let 
x---------> Fernando's distance when Marco is 0.3 miles apart

</span>Fernando funs at a rate of 7.2 miles per hour
<span>for distance =x
time=x/7.2------> equation 1

</span>Marco runs at a rate of 6 miles per hour. 
for distance=x-0.30
time=(x-0.30)/6------> equation 2

equate equation 1 and equation 2
 7.2*(x-0.3)=6x-----> 7.2x-2.16=6x
7.2x-6x=2.16------> x=2.16/1.2-------> x=1.8 miles

time=x/7.2-----1.8/7.2=0.25 hour
6 0
3 years ago
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