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Citrus2011 [14]
3 years ago
10

Could you tell me howto do pls​

Mathematics
1 answer:
dangina [55]3 years ago
7 0

Answer:

f) 60+x+30=180°

90+x=180°

x=180-90

x=90°

g) y+35+75=180°

y+110=180

y=180-110

y=70°

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When it is 11 a.m. in Johannesburg, it is 6 p.m. the same day in Tokyo, Japan. A flight leaves OR Tambo in Johannesburg at 6 a.m
kiruha [24]

Answer:

Dear User,

Answer to your query is provided below

The time will be 8am on Wednesday when flight arrive in Tokyo.

Step-by-step explanation:

Here, You can see that when 11 a.m. in Johannesburg, it is 6 p.m. the same day in Tokyo, Japan ; this means 7Hrs. gap.

Further, A flight leaves Johannesburg at 6 a.m. on Tuesday for Tokyo takes 18 hours in the air, with an additional 1 hour stop-over on land.

So, 6a.m. + 18hr.+1hr.+7hr. = 8am on Wednesday in Tokyo (Arrival)

4 0
3 years ago
Find the indicated products.<br> (3x-5)(3x+5)
frutty [35]
9x²- 25


3x(3x) = 9x²
3x(5) = 15x
-5(3x) = -15x
-5(5) = -25
9x² + 15x - 15x - 25
9x² - 25 is your answer

hope this helps
8 0
3 years ago
Read 2 more answers
Find the inverse of the given relation.
Greeley [361]

Answer:

C

Step-by-step explanation:

first look at all the numbers in the relation.then since inverse means opposite find the answers where the numbers in the parenthesis are in the opposite order than the question. Finally look for the answer In which all the positive numbers in the parenthesis(in the given relation) are negative (on the answers)and the negative numbers (in the given relation) are positive (on the answers).

4 0
4 years ago
Quadrilateral ABCD has the following
a_sh-v [17]

Answer:

No because the angle of point C is NOT congruent to the angle of point A.

Step-by-step explanation:

A quadrilateral MUST be a parallelogram if it has both pairs of its opposite angles congruent.

4 0
3 years ago
Suppose triangle ABC has vertices at A(1, 0), B(10, 0), and C(2, 6). After a 60° counterclockwise rotation about the origin, ver
Artemon [7]
Check the picture attached.

Let OB be the radius of circle with center O.

Let B' be the image of B after the described rotation

OB and OB' are sides of the equilateral triangle OBB'.

The x coordinate of B' is the midpoint of OB, that is 5.

In the right triangle B', point (5, 0) and B:

Distance point (5, 0) to B is 5
|B'B|=|OB|=10

so by the pythagorean theorem:

a= \sqrt{ 10^{2} - 5^{2} } = \sqrt{ 2^{2} *5^{2} - 5^{2} }= \sqrt{5^{2}(4-1)}=5 \sqrt{3} units



Answer: 5 \sqrt{3}

3 0
3 years ago
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