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givi [52]
3 years ago
12

Which step should be performed first in the expression? Then simplify the expression. 5(-3)+6

Mathematics
1 answer:
BabaBlast [244]3 years ago
4 0

Answer:

5(-3) would be the first step

Step-by-step explanation:

5 * -3 = -15

-15 + 6 = -9

-9 is the answer

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The domain of startfraction f over g endfraction f g consists of numbers x for which g left parenthesis x right parenthesisg(x)
Misha Larkins [42]

The domain of f/g consists of numbers x for which g(x) cannot equal 0 that are in the domains of both f and g.

 

Let’s take this equation as an example:

If f(x) = 3x - 5 and g(x) = square root of x-5, what is the domain of (f/g)x. 


For x to be in the domain of (f/g)(x), it must be in the domain of f and in the domain of g since (f/g)(x) = f(x)/g(x). We also need to ensure that g(x) is not zero since f(x) is divided by g(x). Therefore, there are 3 conditions.

 

x must be in the domain of f: f(x) = 3x -5 are in the domain of x and all real numbers x.

x must be in the domain of g: g(x) = √(x - 5) so x - 5 ≥ 0 so x ≥ 5.

g(x) can not be 0: g(x) = √(x - 5) and √(x - 5) = 0 gives x = 5 so x ≠ 5.

 

Hence to x x ≥ 5 and x ≠ 5 so the domain of (f/g)(x) is all x satisfying x > 5.

 

Thus, satisfying <span>satisfy all three conditions, x x ≥ 5 and x ≠ 5 so the domain of (f/g)(x) is all x satisfying x > 5.</span>

5 0
3 years ago
Solve G(x) for the given domain.<br> G(x) = 3x2 - 2x - 1<br> G(6) =
Elina [12.6K]

Answer:

95

Step-by-step explanation:

G(6)=3(6)^2-2(6)-1

=108-12-1

=95

8 0
3 years ago
I will give branlest if your wright
Lelu [443]

Answer:

B

Step-by-step explanation:

Because all whole numbers are integers, but not all integers are whole numbers.

Hope this helps! :)

4 0
3 years ago
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Answer:

6

Step-by-step explanation:

The area of each of the squares is 3. There's 2 so it's 6.

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3 years ago
a plumber charges $52.50 per hour plus a $75.00 service charge your father's firm hires him to fix some leaky pipes find the tot
aleksley [76]

(4.5 x 52.5) + 75 = 311.25

7 0
3 years ago
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