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2 years ago

PLEASE EXPLAIN AND HELP WILL MARK BRAINLIEST

Mathematics

1 answer:

vagabundo [1.1K]2 years ago

5 0

Answer:

I dunno this one, u should

Step-by-step explanation:

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Can someone please help me with this question.

rusak2 [61]

25x25+20x25+20x15+15x25=1800 the answer is D.

5 0

3 years ago

Jacob leaves his summer cottage and drives home. After

krok68 [10]

Answer:

A linear relationship can be written as:

y = a*x + b

Where a is the slope and b is the y-intercept.

If this line passes through the points (a, b) and (c, d) then the slope can be written as:

a = (a - c)/(b - d)

Here y will represent the distance between Jacob and his house, and the variable x represents the time that he has ben driving.

In this case, we know that after driving for 5 hours, he is 112km from home.

Then we can write this point as (5h, 112km)

We also know that after 7 hours he is 15km from home.

Then we can write this point as (7h, 15km)

Then the slope of this function will be:

a = (15km - 112km)/(7h - 5h) = -48.5 km/h

Then the equation is:

y = -(48.5 km/h)*x + b

To find the value of b, we can replace the values of one of the points, for example in the point (7h, 15km)

This means that we need to replace x by 12h, and y by 15km, then we get:

15km = -( 48.5 km/h)*7h + b

15km + ( 48.5 km/h)*7h = b = 354.5 km

then the equation will be:

y = (-48.5 km/h)*x + 354.5 km

Now we want to answer: How long had Jacob been driving when he was 209 km from home?

Then we need to only replace y by 209km, and solve for x:

209km = (-48.5 km/h)*x + 354.5 km

209km - 354.5 km = (-48.5 km/h)*x

-145.5km = (-48.5 km/h)*x

-145.5km/( -48.5 km/h) = x = 3h

So he is 209km away from his home after driving for 3 hours.

6 0

3 years ago

If a jogger runs 2 miles and burns 185 calories, how many calories would he burn if he jogged 3 miles?

aliina [53]

The total amount of calories burnt in jogging 2 miles = 185 calories

We have to determine the number of calories burned in jogging 3 miles.

Firstly, we will determine the amount of calories burnt in jogging 1 mile. We will use unitary method to evaluate this.

So, the total amount of calories burnt in jogging 1 mile = $185 \div 2$

= 92.5 calories

So, the amount of calories burnt in 3 miles = $3 \times 92.5$

= 277.5 calories

Therefore, 277.5 calories are burned in jogging 3 miles.

6 0

3 years ago

Read 2 more answers

Thaddeus wants to attend a sports camp this spring that costs $170.00 for the week. He rakes leaves during the fall and earns $5

AnnyKZ [126]

The answer to this question is 25.85

5 0

3 years ago

Read 2 more answers

Find the standard form of the circle x2 + y2 – 6x + 10y + 24 = 0 by completing the square.

hichkok12 [17]

Answer:

$(x-3)^2+ (y+5)^2=10$

Step-by-step explanation:

Given the equation of the circle: $x^2 + y^2 - 6x + 10y + 24 = 0$

We wish to express it in a Standard form:

We begin by re-arranging:

$x^2 - 6x + y^2 + 10y = - 24$

Next, divide the coefficient of x by 2, square it and add it to both sides.

Do the same for y.

$x^2 - 6x +(-3)^2+ y^2 + 10y+5^2 = - 24+(-3)^2+5^2$

Next, we factorize

$(x-3)^2+ (y+5)^2 = - 24+9+25\\(x-3)^2+ (y+5)^2=10$

This is the standard form.

6 0

3 years ago