Answer:
<em>☆</em><em><</em><em> </em><em><u>《</u></em><em><u>HOPE IT WILL HELP YOU</u></em><em>》</em><em>></em><em>☆</em>
Step-by-step explanation:
Y=1.5x+2
<h3>
<em><u>(</u></em><em><u>x</u></em><em><u>=</u></em><em><u>1</u></em><em><u>)</u></em></h3>
y=1.5 (1) +2
y=1.5+2
y=3.5
<h3>
<em><u>(</u></em><em><u>x</u></em><em><u>=</u></em><em><u>2</u></em><em><u>)</u></em></h3>
y=1.5(2)+2
y=3+2
y=5
<h3>
<em><u>(</u></em><em><u>x</u></em><em><u>=</u></em><em><u>3</u></em><em><u>)</u></em></h3>
y=1.5 (3)+2
y=4.5+2
y=6.5
<h3>(x=4)</h3>
y=1.5 (4)+2
y=6+2
y=8
<h3>
<em><u>(</u></em><em><u>x</u></em><em><u>=</u></em><em><u>5</u></em><em><u>)</u></em></h3>
y=1.5 (5)+2
y=7.5+2
y=9.5
<h2>
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Answer:
a.y'=-1
b.y'=-1
c.Yes
Step-by-step explanation:
We are given that consider a function

Implicit function: That function is a relation in which dependent variable can not be expressed in terms of independent variable
Explicit function: It is that function in which dependent variable can be expressed in terms of independent variable.
a.
Differentiate w.r.t x then we get




b.


Differentiate w.r.t x then we get


When we substituting the value of y obtained from part b into a solution of part a then we get

Hence, solutions are consistent.
Answer:
2
Step-by-step explanation:
-2y+10+2y-8
-2y+2y+10-8
10-8
2
Answer:
1. Technically 2, but might be 0 in your teacher's opinion.
2. 1
Step-by-step explanation:
Solving problem one.
So I don't know if you have learned about imaginary numbers, but if you have, then you would end up with two answers if you plugged in the quadratic formula.
If you haven't learned about imaginary numbers, then I would say your best option would be to write 'No real solution' since there are technically 2 solutions.
Solving problem two.
Turns out this quadratic has a special property and it's actually a square of one equation. You can find out by just factoring the equation.
It's (3x-2)^2. Since it's squared, that means that only 2/3 would work as x in this equation.