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raketka [301]
2 years ago
9

The following data represent highway fuel consumption in miles per gallon (mpg) for a random sample of 55 models of passenger ca

rs (Source: Environmental Protection Agency). 30 27 22 25 24 25 24 15 35 35 33 52 49 10 27 18 20 23 24 25 30 24 24 24 18 20 25 27 24 32 13 13 21 2 37 35 32 33 29 3 28 28 25 29 31 For this problem, use five classes. (a) Find the class width. (b) Make a frequency table showing class limits, class boundaries, midpoints, frequencies, relative frequencies, and cumulative frequencies. (Give relative frequencies to 2 decimal places.) Class Limits Midpoint Freqeny Relative |Cumulative (c) Draw a histogram.
Mathematics
1 answer:
Varvara68 [4.7K]2 years ago
7 0

Answer:

11  ;

Step-by-step explanation:

Given the data:

30 27 22 25 24 25 24 15 35 35 33 52 49 10 27 18 20 23 24 25 30 24 24 24 18 20 25 27 24 32 13 13 21 2 37 35 32 33 29 3 28 28 25 29 31

Number of classes = 5

Class width : Range / number of classes

Class width = (maximum - minimum) / 5

Class width = (52 - 2) / 5 = 50/5 = 10 + 1 = 11

For the frequency table showing class limits, class boundaries, midpoints, frequencies, relative frequencies, and cumulative frequencies and histogram

Kindly check attached picture

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Answer:

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A rectangle has an area of 19.38 cm2. When both the length and width of the rectangle are increased by 1.50 cm, the area of the
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Answer: 5.7\ cm

Step-by-step explanation:

Given

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We can write

\Rightarrow lw=19.38\quad \ldots(i)\\\\\Rightarrow (l+1.5)(w+1.5)=35.28\\\Rightarrow lw+1.5(l+w)+1.5^2=35.28\\\text{use (i) for}\ lw\\\Rightarrow 19.38+1.5(l+w)=35.28-2.25\\\Rightarrow l+w=9.1\quad \ldots(ii)

Substitute the value of width from (ii) in equation (i)

\Rightarrow l(9.1-l)=19.38\\\Rightarrow l^2-9.1l+19.38=0\\\\\Rightarrow l=\dfrac{9.1\pm\sqrt{(-9.1)^2-4(1)(19.38)}}{2\times 1}\\\\\Rightarrow l=\dfrac{9.1\pm\sqrt{5.29}}{2}\\\\\Rightarrow l=\dfrac{9.1\pm2.3}{2}\\\\\Rightarrow l=3.4,\ 5.7

Width corresponding to these lengths

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Therfore, we can write the length of the longer side is 5.7\ cm

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