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zhenek [66]
3 years ago
15

Volume of this cone

Mathematics
1 answer:
ArbitrLikvidat [17]3 years ago
7 0

Answer:

669.9 ft³

Step-by-step explanation:

The formula for volume of a cone:

v=\pi r^2*\frac{h}{3} (3.14*radius*radius*\frac{height}{3} )

r = radius,\pi =pi,h=height.

The radius is 8; the height is 10.

From here, we can just plug the numbers into the formula.

\pi 8^2*\frac{10}{3} (3.14*8*8*\frac{10}{3} ) = 669.866666667.

669.866666667 ≈ 669.9.

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The correct answer is

D) 66.35

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Health insurers are beginning to offer telemedicine services online that replace the common office visit. A company provides a v
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Answer:

\text {CI} = (60.54, \: 81.46)\\\\

Therefore, we are 95% confident that actual mean savings for a televisit to the doctor is within the interval of ($60.54 to $81.46)

Step-by-step explanation:

Let us find out the mean savings for a televisit to the doctor from the given data.

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=AVERAGE(number1, number2,....)

The mean is found to be

\bar{x} = \$71  

Let us find out the standard deviation of savings for a televisit to the doctor from the given data.

Using Excel,

=STDEV(number1, number2,....)

The standard deviation is found to be

 s = \$ 22.35

The confidence interval is given by

\text {confidence interval} = \bar{x} \pm MoE\\\\

Where the margin of error is given by

$ MoE = t_{\alpha/2}(\frac{s}{\sqrt{n} } ) $ \\\\

Where n is the sample of 20 online doctor visits, s is the sample standard deviation and t_{\alpha/2} is the t-score corresponding to a 95% confidence level.

The t-score is given by is

Significance level = α = 1 - 0.95 = 0.05/2 = 0.025

Degree of freedom = n - 1 = 20 - 1 = 19

From the t-table at α = 0.025 and DoF = 19

t-score = 2.093

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MoE = t_{\alpha/2}(\frac{s}{\sqrt{n} } ) \\\\MoE = 2.093\cdot \frac{22.35}{\sqrt{20} } \\\\MoE = 2.093\cdot 4.997\\\\MoE = 10.46\\\\

So the required 95% confidence interval is

\text {CI} = \bar{x} \pm MoE\\\\\text {CI} = 71 \pm 10.46\\\\\text {CI} = 71 - 10.46, \: 71 + 10.46\\\\\text {CI} = (60.54, \: 81.46)\\\\

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