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Sedbober [7]
2 years ago
7

What is the area of this trapezoid Enter your answer in the box​

Mathematics
2 answers:
Oksanka [162]2 years ago
8 0

Answer:

468 sq. ft.

Step-by-step explanation:

A = 1/2 (a + b) (h)

   = 1/2 (52) (18)

   = 468 sq. ft.

aalyn [17]2 years ago
8 0

Solution:

<u>Note that:</u>

  • Area of trapezoid: (a₁ + a₂/2)h
  • a₁ = 15 ft.
  • a₂ = 37 ft.
  • h = 18 ft.

<u>Use the formula to find the area.</u>

  • (a₁ + a₂/2)h
  • => (15 + 37/2)18
  • => (52/2)18
  • => 26 x 18
  • => 468 ft.²

The area of the trapezoid is 468 ft.²

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Nine pieces of 8 in. ✕ 12 in. duct that is 2 2 3 ft in length is needed for a building. What is the total length (in ft) needed?
kodGreya [7K]

This question is incomplete, the complete question is;

Nine pieces of 8-in. × 12-in. duct that is 2\frac{2}{3} ft in length is needed for a building. What is the total length (in ft) needed?

Answer:

the total length needed is 24 ft

Step-by-step explanation:  

Given the data in the question;

the length of one piece of 8-in. × 12-in. duct is 2\frac{2}{3} ft

Now to find the total length for nine pieces of the duct;

we simple multiply 2\frac{2}{3} ft  by nine

so

Total length = 9 × 2\frac{2}{3}  

we convert the mixed fraction to improper fraction

2\frac{2}{3}  = 8/3

so

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Therefore, the total length needed is 24 ft

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3 years ago
Simplify the following
Darina [25.2K]

Answer:

The answer to your question is the letter B. 5y³ - 18y² + 29y - 12  

Step-by-step explanation:

Data

           (y² - 3y + 4)(5y - 3)

Process

1.- Multiply the first terms by 5y

           (y² - 3y + 4)(5y) = 5y³ - 15y² + 20y

2.- Multiply the first terms by -3

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3.- Simplify like terms

            5y³ - 15y² + 20y  -3y² + 9y - 12 = 5y³ + (-15y² - 3y²) + (20y + 9y) -12

4.- Result

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weqwewe [10]

Answer:

114

Step-by-step explanation:

456 devided by 4 equals 114

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f(x)=\frac{(2x+1)(x-5)}{(x-5)(x+4)^2}

The domain is

(x-5)(x+4)^2\ne 0

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x\ne5,x\ne -4

ii) For vertical asymptotes, we simplify the function to get;

f(x)=\frac{(2x+1)}{(x+4)^2}

The vertical asymptote occurs at

(x+4)^2=0

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iii) The roots are the x-intercepts of the reduced fraction.

Equate the numerator of the reduced fraction to zero.

2x+1=0

2x=-1

x=-\frac{1}{2}

iv) To find the y-intercept, we substitute x=0 into the reduced fraction.

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f(0)=\frac{(1)}{(4)^2}

f(0)=\frac{1}{16}

v) The horizontal asymptote is given by;

lim_{x\to \infty}\frac{(2x+1)}{(x+4)^2}=0

The horizontal asymptote is y=0.

vi) The function has a hole at x-5=0.

Thus at x=5.

This is the factor common to both the numerator and the denominator.

vii) The function is a proper rational function.

Proper rational functions do not have oblique asymptotes.

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