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Masteriza [31]
3 years ago
12

A quadratic in factored form is given as (x + 5) (2x - 3) = 0, what are the solutions of this given equation?

Mathematics
2 answers:
Nikolay [14]3 years ago
6 0

Answer:

Step-by-step explanation:

Pavlova-9 [17]3 years ago
3 0

Answer:

x = -5, x = 1.5

Step-by-step explanation:

If the two expressions multiplied together is 0, that means that one of the expressions would have to equal 0. This gives us two possible answers. Our two equations are now:

x + 5 = 0

2x - 3 = 0

We will first solve the first one!

To isolate x, we subtract 5 from both sides to get:

x = -5

Onto the second one!

We begin to isolate x by adding 3 to both sides.

2x = 3

Now we divide both sides by 2.

x = 3/2 or 1.5

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The table and graph both represent the same relationship.
Llana [10]

Answer:

x = 1

Step-by-step explanation:

From the table shown in the picture,

For input value x = 1, output values of y = 2, 4, 6, 8, 10

Similarly, from the graph shown,

For input value x = 1, output values of y = 2, 4, 6, 8, 10

Therefore, both will represent the same relationship.

From the graph attached, straight line parallel to y-axis is x = 1.

Therefore, x = 1 will be the correct option.

3 0
3 years ago
What's the answer? I need help asap
Bogdan [553]

The two triangles are congruent through AA (angle-angle proportionality theorem) therefore all the sides are congruent to each other.

In this case:

2y = 5y - 7

2y - 5y = -7

-3y = -7

y = -7/-3

y = 7/3

8 0
3 years ago
Given certain information, what is the value of x4-y4?
Pepsi [2]

Well right off the bat, I can see a good reason why it should boggle.

If (x+y)=6 and (x-y)=2, then (x+y)(x-y) would be 12. It can't be 20.

The first 4 lines on the paper are inconsistent, so the question in the 5th line can't be calculated.

Another possible source of uncertainty (for us, anyway) is the remarkable similarity between the way you write ' Y ' and the way you write ' 4 ' . For example, look at the ' Y⁴ ' (I think ...) in the last line.

3 0
3 years ago
A student walk 60m on a bearing
Katena32 [7]

Answer:

d = 234.6 m

Step-by-step explanation:

You can consider a system of coordinates with its origin at the beginning of the walk of the student.

When she start to walk, she is at (0,0)m. After her first walk, her coordinates are calculated by using the information about the incline and the distance that she traveled:

x_1=60cos28\°=52.97m\\\\y_1=60sin28\°=28.16m

she is at the coordinates (52.97 , 28.16)m.

Next, when she walks 180m to the east, her coordinates are:

(52.97+180 , 28.16)m = (232.97 , 28.16)m

To calculate the distance from the final point of the student to the starting point you use the Pythagoras generalization for the distance between two points:

d=\sqrt{(x-x_o)^2+(y-y_o)^2}\\\\x=232.97\\\\x_o=0\\\\y=28.16\\\\y_o=0\\\\d=\sqrt{(232.97-0)^2+(28.16-0)^2}m=234.6m

The displacement of the student on her complete trajectory was of 234.6m

8 0
3 years ago
The length of a rectangle is 5/2 units greater than twice its width. If its width is w, which expression gives the perimeter of
miv72 [106K]
L=5/2*2w=5w
P=(5w+w)*2=12w
Perimeter is 12w
7 0
4 years ago
Read 2 more answers
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