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DiKsa [7]
2 years ago
6

Prove: a/(b+c)+b/(a+c)+c/(a+b)<2

Mathematics
1 answer:
faust18 [17]2 years ago
4 0

Answer:

Step-by-step explanation:

a/(b+c) < 2a/(a+b+c)

b/(a+c) < 2b/(a+b+c)

c/(a+b) <2c/ (a+b+c)

so a/(b+c)+b/(a+c)+c/(a+b) <2(a+b+c)/(a+b+c)=2

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Step-by-step explanation:

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∠ABC = 2x-15

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∠ABC + < BCD= π ( 180° in radiant)

2x - 15 + 3x = π

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= 3.628318531 = 207.8873386

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2 years ago
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3 years ago
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anzhelika [568]

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What is the x and y coordinate of (3,4)

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3 years ago
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Read 2 more answers
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