3 years ago

Prove: a/(b+c)+b/(a+c)+c/(a+b)<2

Mathematics

1 answer:

faust18 [17]3 years ago

4 0

Answer:

Step-by-step explanation:

a/(b+c) < 2a/(a+b+c)

b/(a+c) < 2b/(a+b+c)

c/(a+b) <2c/ (a+b+c)

so a/(b+c)+b/(a+c)+c/(a+b) <2(a+b+c)/(a+b+c)=2

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