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3 years ago

Only 2 Questions.. Please Help.

1 answer:

5 0

Number 2 depends because u might be lookin for the zeros or an intersection. If u lookin for the zeros u look at the x intercept.

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Need help with this geometric question ASAP, Thank you

Harlamova29_29 [7]

Answer: 15

Step-by-step explanation:

6 0

2 years ago

BC = 5, AC = 6, sin C = 4/5. What is the area of △ABC?

jok3333 [9.3K]

Hmmmmmmmmmmmmmmmmmmmmmmmmmm

8 0

3 years ago

A deposit earns interest at a rate of r percent compounded continuously and doubles in value in 9 years. Find r. (Round your ans

AVprozaik [17]

Answer:

The earning rate is approximately 0.08.

Step-by-step explanation:

We can determine the yearly rate by means of compound interest, which is defined by:

$C(t) = C_{o}\cdot (1+r)^{t}$ (Eq. 1)

Where:

$C_{o}$ - Initial deposit, measured in US dollars.

$r$ - Earning rate, dimensionless.

$t$ - Earning periods, measured in years.

We proceed to clear the earning rate within:

$\frac{C(t)}{C_{o}} = (1+r)^{t}$

$\log \frac{C(t)}{C_{o}} = t\cdot \log (1+r)$

$\frac{1}{t}\cdot \log \frac{C(t)}{C_{o}} = \log (1+r)$

$\log \left(\frac{C(t)}{C_{o}} \right)^{\frac{1}{t} } = \log (1+r)$

$\left(\frac{C(t)}{C_{o}} \right)^{\frac{1}{t} } = 1+r$

$r = \left(\frac{C(t)}{C_{o}} \right)^{\frac{1}{t} }-1$

If we know that $C(9) = 2\cdot C_{o}$ and $t = 9$ , then the earning rate is:

$r = 2^{\frac{1}{9} }-1$

$r \approx 0.08$

The earning rate is approximately 0.08.

8 0

3 years ago

Can you tell me what pi is ?

sammy [17]

Pi is actually one of the letters of the Greek alphabet, but it is most known in the math field as the ratio between the circumference of a circle and the circle's diameter.

There is no exact measure of pi, as it does not terminate but it starts like:

3.14159265

8 0

3 years ago

Read 2 more answers

Adult panda weights are normally distributed with a mean of 200 pounds and a standard deviation of 50 pounds. The largest pandas

joja [24]

Answer:

16%

Step-by-step explanation:

THERE

4 0

3 years ago

Read 2 more answers