Question

I really need this help

Answer 1

Answer:

area: 454.2 sq.cm

perimeter: 77.7 cm

Step-by-step explanation:

to find area, find the area of all the separate shapes and add them together:

semi-circle:

radius is 12 cm

area = $\frac{\pi (12)^2\\}{2}$ = 226.2 sq.cm

separate the trapezoid into two right triangles and a rectangle.

area for triangles:

$\frac{1}{2}$(5)(12) = 30

30 x 2 = 60 sq.cm (since there are two triangles)

area for rectangle:

12 x 14 = 168 sq.cm

area of whole shape: 226.2 + 60 + 168 = 454.2 sq.cm

for perimeter, just add the length of the exterior sides together.

we have some unknown sides, such as the semicircle and the sides of the trapezoid

we can find the hypotenuse of the triangles we used earlier to find the sides of the trapezoid with pythagorean theorem

$5^2 + 12^2 = c^2$

$25 + 144 = c^2$

$169 = c^2$

$\sqrt{169} =\sqrt{c^2}$

c = 13 cm

to find the outside perimeter of the semi-circle, solve as if you were finding the circumference of a normal circle and divide it in half

$\frac{2\pi12}{2}$ = 37.7 cm

now add it all up:

14 + 13 + 13 +37.7 = 77.7