Answer:
A. VG = 80
B. Broad sense heritability = 0.80
C. Narrow sense heritability = 0.30
D. Average yield = 430 Units
Explanation:
A. Given that
VA = 30
VD = 50
VI = assumed not available
Therefore
Total genetic variance (VG) = VA + VD
= 30 + 50
= 80
VG = 80
B. Given that
VP = 100
VG = 80
Broad sense heritability, H2 = VG/VP
= 80/100
= 0.80
C. Given that
VA = 30
VP = 100
Narrow sense heritability, h2 = VA/VP
=30/100
= 0.30
D. The difference in selection = 500 - 400
= 100
Recall,
Selection response is heritability multiplied by selection differential.
That is
R = h2S
Selection differential = 100
Heritability h2 = 0.30
Selection response = 0.30 × 100
= 30units
Therefore, expected average yield = 400 + 30
= 430 Units
Answer:
mutation,recobmadation, and immitigation
Answer:
The correct answer would be b. Their numbers will soon decrease.
Bobcats are opportunistic carnivores that feed on various types of prey such as mice, rabbits, voles, mountain beaver, gophers, yellow-bellied marmots, insects, birds, reptiles, and carrion.
If a group of Bobcats moves at the bottom of the mountain, then they will start hunting and eating all the prey available in the area.
It will result in the rapid decrease in the population of preys.
D. Mutations involved the genetic variation of the bugs are random
