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3 years ago

90 units needed 8per case

1 answer:

6 0

Are you asking how much cases is needed to to reach the 90 units? If yes then 90/8 which would give you 11.25. But since it’s by case then round up to get 12 cases. I think I answered it wrong but

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Evaluate A 2-B 2 for A = 3 and B = -4.<br><br> -7<br> -2<br> 25

kogti [31]

$A^2-B^2$
Substitute the values of A = 3 and B = -4 to the expression:
$3^2-(-4)^2=9-16=-7$

6 0

3 years ago

Pls help it’s 10 points

Yuliya22 [10]

Answer:

An féidir leat níos mó de phléasc a thabhairt?/

Step-by-step explanation:

5 0

3 years ago

Joyville has a population of 20,750 people.

Vika [28.1K]

560 people move to Joyville each year.
I just used a calculator.. and put ( 20,750 + 2.7% = 560.25) so hopefully that helps!

6 0

3 years ago

The initial value of a quantity Q (at year t = 0) is 112.8 and the quantity is decreasing by 23.4% per year. a) Write a formula

Svetach [21]

Answer:

a) $Q(t) = 112.8*(0.766)^{t}$

b) When t = 10, Q = 7.845.

Step-by-step explanation:

The value of a quantity after t years is given by the following formula:

$Q(t) = Q_{0}(1 + r)^{t}$

In which $Q_{0}$ is the initial quantity and r is the rate that it changes. If it increases, r is positive. If it decreases, r is negative.

a) Write a formula for Q as a function of t.

The initial value of a quantity Q (at year t = 0) is 112.8.

This means that $Q_{0} = 112.8$ .

The quantity is decreasing by 23.4% per year.

This means that $r = -0.234$

$Q(t) = 112.8*(1 - 0.234)^{t}$

$Q(t) = 112.8*(0.766)^{t}$

b) What is the value of Q when t = 10?

This is Q(10).

$Q(t) = 112.8*(0.766)^{t}$

$Q(t) = 112.8*(0.766)^{10} = 7.845$

When t = 10, Q = 7.845.

4 0

4 years ago

Help with this problem.

ValentinkaMS [17]

15 is the answer I think because that is the Greatest Common Factor of all three of them.

I hope this helps!

5 0

3 years ago