If an items weight is 0 it would be like a peice of paper or cotten ball. when a cotten ball is weighed it does not affect anything. as when a peice of paper is wieghed it moves its meater 1 inch.
Ok so for starters you want to choose an equation and solve for a variable.
So, I am going to choose x from the first equation.
Add y to both sides and you get x=11+y
Next, substitute 11+y for x in the other equation so you get...
2(11+y) +10y=-6
Next distribute the 2 throug the 11 and the y
22+2y+10y=-6
12y=-28
y=-28/12
reduce this fraction to make this easier.
y=-7/3
Now plug in why to either of the equations to find x
x-(-7/3)=11
x+7/3=11
x=11-(7/3)
x=(33/3)-(7/3)
x=26/3
so x = 26/3 and y = -7/3
you can also check to see if this is correct by substituting each of these values into the equations.
We want to find the coeficient of the y terms when added together so find all the y terms
+12y and +2y
we add them together
12y+2y=(12+2)y=(14)y=14y
coeficient is 14
the constant is the number that is set already or the number that doesn't have it multiplied by a placeholder exg. 4 is a constnat but 4x is not so find the constants
+5 and +8
we add
5+8=13
the constant is 13
y coeficient=14
constant=14
Tanya run 50 yards across the diagonal of the rectangular field.
<u>Step-by-step explanation</u>:
Step 1 :
- Length of the rectangular field = 40 yards
- width of the rectangular field = 30 yards
Step 2 :
Measure of the diagonal = √(length^2 + width^2 )
Step 3 :
Diagonal = √(40^2 + 30^2 )
= √(1600 + 900)
= √2500
= ±50
Step 4 :
Since distance cannot be negative, The measure of diagonal = 50 yards.
∴ Tanya runs diagonally across a rectangular field is 50 yards.
