The formula for the area of a trapezoid is:
A= (a+b)/2*h
A=150
h=10
b=14
a=?
So we need to solve for a. Let's plug in the values that we do know...
A= (a+b)/2*h
150=(a+14)/2*10
150=(a/2+14/2)*10
150=(a/2+7)*10
Divide both sides by 10
15=a/2+7
subtract 7 from both sides
8=a/2
multiply both sides by 2
16=a
The other base is 16
Answer:
the answer to that is B hope it helps
Answer:
x = 9, y = 2 is the solution of the given system.
Step-by-step explanation:
Here, the given set of equation is :
2 x - 3 y = 12
x = 4 y + 1
Now, from equation (2) we see that x = 4 y + 1.
Substitute the value of y from (2) in the first equation. we get:
2 x - 3 y = 12 ⇒ 2 (4 y + 1) - 3 y = 12
or, 8 y + 2 - 3 y = 12
or, 5 y = 12- 2 = 10
or, y = 10/ 5 = 2
or, y = 2
Now, x = 4 y + 1 ⇒ x = 4(2) + 1 = 8 + 1 = 9, or x = 9
Hence, x = 9, y = 2 is the solution of the given system.
Just flip your fraction around and your answer will be 10/11
The hypotenuse would be 9 inches as 6 is equal to 2/3 of 9 :)
