1)
2(a + 3) = -12
Divide by 2
a + 3 = -6
Subtract 3
a = -9
2)
3(p + 2) = 18
Divide by 3
p + 2 = 6
Subtract 2
p = 4
3)
4(2r + 8) = 88
Dive by 4
2r + 8 = 22
Subtract 8
2r = 14
Divide by 2
r = 7
4)
2(3a + 2) = -8
Divide by 2
3a + 2 = -4
Subtract 2
3a = -6
Divide by 3
a = -2
5)
4(k + 3) = 4
Divide by 4
k + 3 = 1
Subtract 3
k = -2
It will be 90 feet considering the water triangle as shown as the figure
Solution :
Let 
and 
represents the proportions of the seeds which germinate among the seeds planted in the soil containing 
and 
mushroom compost by weight respectively.
To test the null hypothesis 
against the alternate hypothesis 
.
Let 
denotes the respective sample proportions and the 
represents the sample size respectively.
The test statistic can be written as :
which under 
follows the standard normal distribution.
We reject at 
level of significance, if the P-value 
or if 
Now, the value of the test statistics = -1.368928
The critical value = 
P-value = 
= 0.171335
Since the p-value > 0.05 and 
, so we fail to reject at level of significance.
Hence we conclude that the two population proportion are not significantly different.
Conclusion :
There is not sufficient evidence to conclude that the 
of the seeds that 
with the percent of the 
in the soil.
