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Rom4ik [11]
2 years ago
10

What is the point-slope form of a line with a slope -3 that contains the point (10,-1)

Mathematics
1 answer:
Citrus2011 [14]2 years ago
4 0
<h2>y + 1 = -3(x - 10)</h2>

Here's the formula:

y - y1 = m(x - x1)

Substitute numbers accordingly:

y1: so 1 goes in the y1 spot (you switch the signs because it was already negative)

x1:  and 10 goes to the x1 spot

m:  -3 belongs in m

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Sam received a 15 percent tip for delivering pizzas. If the cost of the pizzas was $247.62, what was the total amount he collect
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I hope that helped :)
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3 years ago
What is BC?<br><br> BC= units
hodyreva [135]

Answer:

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Step-by-step explanation:

6 0
3 years ago
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Find the area of the triangle formed by the origin and the points of intersection of parabolas y=− 1/3 (x−1)^2+8 and y=x^2−2x−3.
Kobotan [32]

Answer:

The area of the triangle formed by origin, and the points (4,5) and (-2,5) will be 15 sq. units.

Step-by-step explanation:

The two parabolas are y = - \frac{1}{3}(x - 1)^{2} + 8 and y = x² - 2x - 3.

Now, solving those two equations we will get the points of intersection.

So, - \frac{1}{3}(x - 1)^{2} + 8 = x^{2} - 2x - 3

⇒ - (x - 1)² + 24 = 3x² - 6x - 9

⇒ -x² + 2x - 1 + 24 = 3x² - 6x - 9

⇒ 4x² - 8x - 32 = 0

⇒ x² - 2x - 8 = 0

⇒ x² - 4x + 2x - 8 = 0

⇒ (x - 4)(x + 2) = 0

So, x = 4 or - 2.

Now, for x = 4 , y = 4² - 2(4) - 3 = 5 and the point of intersection is (4,5).

Or, for x = - 2, y = (- 2)² - 2(- 2) - 3 = 5 and the point of intersection is (-2,5).

Now, points (4,5) and (-2,5) make a straight line parallel to the x-axis at a perpendicular distance of 5 units from origin and its length is (4 - (- 2)) = 6 units.

So, the area of the triangle formed by origin, and the points (4,5) and (-2,5) will be = 0.5 × 5 × 6 = 15 sq. units. (Answer)

8 0
3 years ago
Can someone help me please
schepotkina [342]

Answer:

∠B=60°

Step-by-step explanation:

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5 0
3 years ago
Solve for p: 5(4x+p)=w
Olenka [21]
P = w/5 - 4x is the answer
6 0
2 years ago
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