Answer: The required probability of selecting 1 red apple and 2 yellow apples is 36.36%.
Step-by-step explanation: We are given that a bag contains 6 red apples and 5 yellow apples out of which 3 apples are selected at random.
We are to find the probability of selecting 1 red apple and 2 yellow apples.
Let S denote the sample space for selecting 3 apples from the bag and let A denote the event of selecting 1 red apple and 2 yellow apples.
Then, we have
Therefore, the probability of event A is given by
Thus, the required probability of selecting 1 red apple and 2 yellow apples is 36.36%.
Answer:
28.27
Step-by-step explanation:
Area= pi x radius squared
Radius is 1/2 the diameter which in this case is 6 ft
So, pi x 3 squared (9)
= 28.27
Answer:
When n=3 and x=−2 the answer is 11.
Step-by-step explanation:
Given:
Let p (n,x) be the function such that
To Find:
p (n,x) = p ( 3, -2) = ?
Solution:
Substituting n = 3 and x = -2 we get
Negative square gives positive number therefore (-2)²=4
When n=3 and x=−2 the answer is 11.
1m = 100 cm
so
40 m = 4,000 cm
25 m = 2,500 cm
10 m = 1,000 cm
perimeter of big rectangle = 2(4,000 + 2000) = 12,000 cm
perimeter of small rectangle on the left: 2(2,500 + 800) = 6,600 cm
perimeter of small rectangle on the right: 2(1,000 + 800) = 3,600 cm
perimeter of circle = πd = 3.141593 x 200 = 628.32 cm
total area of the pitch and seating area :
= 12,000 + 6,600 + 3,600 + 628.32 = 22,828.32<span> cm
answer
</span>22,828.32 cm<span>
</span>