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anzhelika [568]
3 years ago
12

What is 1/2 times seven

Mathematics
2 answers:
Ket [755]3 years ago
5 0
1/2 of 7 is
1/2 times 7 which is
1/2*7/1
multiply the numerators and denominators to get 7/2, or 
3.5
GREYUIT [131]3 years ago
3 0
3.5 is your answer. :)



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-4 + k/ 2 = -7 Please help guys!
yaroslaw [1]

Answer:

k=-6

Step-by-step explanation:

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There are 10 less red skittles than orange skittles in the bag. The orange skittles are also twice the number of red skittles. F
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20 skittles double the number of red

the red skittles have 10 skittles the orange skittles have 20 so its additon

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30

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Please help in this!
vovikov84 [41]

Step-by-step explanation:

Correct option is C)

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4 0
2 years ago
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Scott was considering the equation 5 - x = 12. He said, "That seems
den301095 [7]

Answer:

-7

Step-by-step explanation:

5 - x = 12  \\ 5 - 12 = x \\   - 7 = x

it is possible because x is just a letter representing the unknown nos

7 0
3 years ago
Patrick has just finished building a pen for his new dog. The pen is 3 feet wider than it is long. He also built a doghouse to p
zalisa [80]

General Idea:

(i) Assign variable for the unknown that we need to find

(ii) Sketch a diagram to help us visualize the problem

(iii) Write the mathematical equation representing the description given.

(iv) Solve the equation by substitution method. Solving means finding the values of the variables which will make both the equation TRUE

Applying the concept:

Given: x represents the length of the pen and y represents the area of the doghouse

<u>Statement 1: </u>"The pen is 3 feet wider than it is long"

Length \; of\; the \; pen = x\\ Width \; of\; the\; pen=x+3

------

<u>Statement 2: "He also built a doghouse to put in the pen which has a perimeter that is equal to the area of its base"</u>

Area \; of\; the\; Dog \; house=y\\ Perimeter \; of\; Dog\; house=y

------

<u>Statement 3: "After putting the doghouse in the pen, he calculates that the dog will have 178 square feet of space to run around inside the pen."</u>

Area \; of \; the\; Pen - Area \;of \;the\;Dog \;House=\;Space\;inside\;Pen\\ \\ x \cdot (x+3)-y=178\\ Distributing \;x\;in\;the\;left\;side\;of\;the\;equation\\ \\ x^2+3x-y=178\Rightarrow\; 1^{st}\; Equation\\

------

<u>Statement 4: "The perimeter of the pen is 3 times greater than the perimeter of the doghouse."</u>

Perimeter\; of\; the\; Pen=3\; \cdot \; Perimeter\; of\; the\; Dog\; House\\ \\ 2(x \; + \; x+3)=3 \cdot y\\ Combine\; like\; terms\; inside\; the\; parenthesis\\ \\ 2(2x+3)=3y\\ Distribute\; 2\; in\; the\; left\; side\; of\; the\; equation\\ \\ 4x+6=3y\\ Subtract \; 6\; and \; 3y\; on\; both\; sides\; of\; the\; equation\\ \\ 4x+6-3y-6=3y-3y-6\\ Combine\; like\; terms\\ \\ 4x-3y=-6 \Rightarrow \; \; 2^{nd}\; Equation\\

Conclusion:

The systems of equations that can be used to determine the length and width of the pen and the area of the doghouse is given in Option B.

178=x^2+3x-y\\ \\ -6=4x-3y

8 0
3 years ago
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