9514 1404 393
Answer:
5 seconds
Step-by-step explanation:
Suppose the front parts of the trains meet at point A. Since both are the same length and traveling the same speed, each will pass point A in time ...
time = distance/speed
time = (1/18 mi)/(40 mi/h) = (1/720 h) × (3600 s)/(1 h) = 5 s
That is, the rear part of each train will be at point A 5 seconds after the front part.
The rear parts will pass each other 5 seconds after the front parts meet.
It’s a little blurry can’t really read it
I think 10 sweaters and 55 dollars left over. :)
Answer:
20 cm²
Refer to the attached page,I've shown the complete calculation over there.
I hope this helps you...
Answer:
S.A. = 150.72
Step-by-step explanation:
S .A. = ![\pi r^{2} + \pi rl](https://tex.z-dn.net/?f=%5Cpi%20r%5E%7B2%7D%20%2B%20%5Cpi%20rl)
4 x 4 x 3.14 = 50.24
3.14 x 4 x 8 = 100.48
100.48 + 50.24 = 150.72