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3 years ago

How do I solve 8x+5y=-20 ?

Mathematics

1 answer:

Vlad [161]3 years ago

4 0

Answer: y=-8/5x-4

Step-by-step explanation:

8x+5y=-20

-8x -8x

5y=-8x-20

/5 /5

y=-8/5x-4

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.99 times .96 equals how much?

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Hi, it should be 0.9504

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3 years ago

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How can this be solved?

Ad libitum [116K]

Answer:

by multiplying all numbers seperatly by each other and adding those

Step-by-step explanation:

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4 years ago

Please help me with precal

Doss [256]

Consider the function $f(x)=\sqrt{x}.$ This function has:

the domain $x\in [0,\infty);$
the range $y\in [0,\infty).$

If the domain of unknown function is $[a,\infty),$ then $x\ge a$ or $x-a\ge 0.$ This means that you have $\sqrt{x-a}$ as a part of needed function.

If the range of unknown function is $[b,\infty),$ then $y\ge b.$ This means that you have to translate function b units up and then the expression of the function is

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Answer: correct choice is B.

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3 years ago

Evaluate the expression when b=2<br> 12-b

exis [7]

Answer:

10 $\huge\checkmark$

Step-by-step explanation:

Hi there, hope you are having a nice day!

All we should do is plug in the value of b:

12-2

10 (Answer)

Hope you find it helpful.

Feel free to ask if you have any questions.

$\bf{-MistySparkles^**^*$

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3 years ago

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the function h(t)=-16t2+144 represents the height, h(t), in feet, of an object from the ground at t second after its dropped. A

blagie [28]

The domain is the limits of the function. Since time doesnt go negative, start with 0. At time 0, the height is

-16(0)^2 + 144 = 144ft

Then, solve for t to find the upper limit for t, which is when the height is zero (since you're dropping the object).

-16t^2 + 144 = 0
-16t^2 = -144
t^2 = 9
t = sqrt(9)
t = 3

The domain is 0 to 3 seconds.

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4 years ago