It's the third one because if you look at the other ones
<u>Answer- </u>
In tossing four fair dice, the probability of getting at most one 3 is 0.86.
<u>Solution-</u>
The probability of getting at most one 3 is, either getting zero 3 or only one 3.
( ∵ xxxx )
( ∵ 3xxx, x3xx, xx3x, xxx3 )
P(Atmost one 3) = P(A) + P(B) = 0.48 + 0.38 = 0.86
Answer:
box is there so I'll put the money in the post
Answer:
y=3
Step-by-step explanation:
To solve this 2 step equation, we need to get y alone. Lets write out the equation
-2y+16=10
Subtract 16 from both sides
-2y-16+16=10-16
Subtract
-2y=-6
divide both sides by -2
-2y/-2=-6/-2
divide
y=3
X² + 2x +3
If the discriminent Δ = b²-4.a.c <0 , that means the roots (or the zero value) are nit REAL Number (they are imaginary or complex)
Δ = 2² - 4(1)3) = 4 - 12 = -8
since Δ = - 8 < 0 there are no real roots
